That can be considered alive.
Answer:
![F = 1.489*10^{-7} N](https://tex.z-dn.net/?f=F%20%3D%201.489%2A10%5E%7B-7%7D%20%20N)
Explanation: Weight of space probes on earth is given by:![W= m*g](https://tex.z-dn.net/?f=W%3D%20m%2Ag)
W= weight of the object( in N)
m= mass of the object (in kg)
g=acceleration due to gravity(9.81
)
Therefore,
![m_{1} = \frac{14500}{9.81}](https://tex.z-dn.net/?f=m_%7B1%7D%20%3D%20%5Cfrac%7B14500%7D%7B9.81%7D)
![m_{1} = 1478.08 kg](https://tex.z-dn.net/?f=m_%7B1%7D%20%3D%201478.08%20%20kg)
Similarly,
![m_{2} = \frac{4800}{9.81}](https://tex.z-dn.net/?f=m_%7B2%7D%20%3D%20%5Cfrac%7B4800%7D%7B9.81%7D)
![m_{2} = 489.29 kg](https://tex.z-dn.net/?f=m_%7B2%7D%20%3D%20489.29%20%20kg)
Now, considering these two parts as uniform spherical objects
Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.
Force between these two objects is given by:
![F = \frac{Gm_{1} m_{2}}{R^{2} }](https://tex.z-dn.net/?f=F%20%3D%20%20%5Cfrac%7BGm_%7B1%7D%20m_%7B2%7D%7D%7BR%5E%7B2%7D%20%7D)
G= gravitational constant (
)
= masses of the object
R= distance between their centres (in m)(18 m)
Substituiting all these values into the above formula
![F = 1.489*10^{-7} N](https://tex.z-dn.net/?f=F%20%3D%201.489%2A10%5E%7B-7%7D%20%20N)
This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.
Dropping a bouncy ball and stretching a rubber ban.