D. a foot model
btw this is a joke right cuz there ain’t no picture lol
Do you see that blank, open space after the word "potential ..." ?
There's supposed to be a number there that actually tells us the value of the potential. Without that number ... and a lot more description of the whole scenario here ... there's no possible answer to the question.
Answer:
The lungs get rid of carbon dioxide and water vapor. The liver gets rid of bile, which, in addition to breaking down fats, is partially made up of the breakdown of red blood cells. The kidneys get rid of toxins from the blood. The large intestine gets rid of undigested food
The kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.
To find the answer, we have to know about the Lorentz transformation.
<h3>What is its kinetic energy as measured in the Earth reference frame?</h3>
It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the kinetic energy as measured in the Earth reference frame, if the landing craft has a mass of 4.00 × 10⁵ kg.
![V_x'=0.8c\\V=0.6c\\m=4*10^5kg](https://tex.z-dn.net/?f=V_x%27%3D0.8c%5C%5CV%3D0.6c%5C%5Cm%3D4%2A10%5E5kg)
- Let us consider the earth as S frame and space craft as S' frame, then the expression for KE will be,
![KE=m_0c^2=\frac{mc^2}{1-(\frac{v_x^2}{c^2} )}](https://tex.z-dn.net/?f=KE%3Dm_0c%5E2%3D%5Cfrac%7Bmc%5E2%7D%7B1-%28%5Cfrac%7Bv_x%5E2%7D%7Bc%5E2%7D%20%29%7D)
- So, to
find the KE, we have to find the value of speed of the approaching landing craft with respect to the earth frame. - We have an expression from Lorents transformation for relativistic law of addition of velocities as,
![V_x'=\frac{V_x-V}{1-\frac{VV_x}{c^2} } \\thus,\\V_x=V_x'(1-\frac{VV_x}{c^2} )+V](https://tex.z-dn.net/?f=V_x%27%3D%5Cfrac%7BV_x-V%7D%7B1-%5Cfrac%7BVV_x%7D%7Bc%5E2%7D%20%7D%20%5C%5Cthus%2C%5C%5CV_x%3DV_x%27%281-%5Cfrac%7BVV_x%7D%7Bc%5E2%7D%20%29%2BV)
- Substituting values, we get,
![V_x=0.8c(1-\frac{0.8c*0.6c}{c^2} )+0.6c=(0.8c*0.52)+0.6c=1.016c](https://tex.z-dn.net/?f=V_x%3D0.8c%281-%5Cfrac%7B0.8c%2A0.6c%7D%7Bc%5E2%7D%20%29%2B0.6c%3D%280.8c%2A0.52%29%2B0.6c%3D1.016c)
![KE=\frac{4*10^5*(3*10^8)^2}{\sqrt{1-\frac{(1.016c)^2}{c^2} } } =\frac{1.2*10^{22}}{0.179}=6.704*10^{22}J](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B4%2A10%5E5%2A%283%2A10%5E8%29%5E2%7D%7B%5Csqrt%7B1-%5Cfrac%7B%281.016c%29%5E2%7D%7Bc%5E2%7D%20%7D%20%7D%20%3D%5Cfrac%7B1.2%2A10%5E%7B22%7D%7D%7B0.179%7D%3D6.704%2A10%5E%7B22%7DJ)
Thus, we can conclude that, the kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.
Learn more about frame of reference here:
brainly.com/question/20897534
SPJ4
The correct answer is:
<span>C) The actual frequency of the siren does not change despite appearances.
In fact, Bob will observe an increase in the apparent frequency as the emergency vehicle approaches him, while Jill will observe a decrease in the apparent frequency as the emergency vehicle moves away from him, because of the Doppler effect (the relative velocity between the observer and the source of the sound is changing), but this effect involves the apparent frequency, while the real frequency of the siren will remain the same.</span>