The kinetic energy of the block when it reaches the bottom is 39.2 J.
<h3>
Kinetic energy of the block at the bottom</h3>
Apply the principle of conservation of energy.
K.E(bottom) = P.E(top)
P.E(top) = mgh
where;
- m is mass of the block
- g is acceleration due to gravity
- h is the vertical height of fall
P.E(top) = 5 x 9.8 x 0.8
P.E(top) = K.E(bottom) = 39.2 J
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The work done by the engine is equal to the gravitational potential energy (GPE) put into it. GPE = mgh
GPE = Work = 1200·9.81·13 = 153,036J
Answer:
Maximum height is20m and time taken will be 2second
Explanation:
vi=20m/s
vf=0m/s
g=10m/s^2
Using third equation for objects falling freely
2gh=(vf)^2-(vi)^2
Putting values
2(10m/s^2)h=(0m/s)^2-(20m/s)^2
20h=400m
h=20m
Now we have to find the time
Using first equation of motion for objects falling down freely
vf=vi+at
substituting the equation
(vf-vi)/g=t
(0-20)/10=t
t=2second
Answer:
I would live in the Atlantic ocean on a lux liner
Explanation:
:)
Find distance she traveled:
100m -25m = 75m
58 seconds / 2 second intervals = 29
29 x 2.6m = 75.4 meters total.
if the distance wasn’t rounded the statement was False.
Answer: False
