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Umnica [9.8K]
3 years ago
12

you and a friend sit still on a spinning merry-go-round. The merry-go-round spins 5 times every second, and to a stationary obse

rver, you have a speed of 9m/s. From your frame of reference, what is the speed of your friend?
Physics
2 answers:
iris [78.8K]3 years ago
6 0

Answer:

the other person is right, the answer is zero.

Explanation:

dedylja [7]3 years ago
4 0

Answer:

  • <u> From your frame of reference, the speed of your friend is zero.</u>

Explanation:

The<em> speed</em> from a <em>frame of reference</em> is the magnitude of the change of the position per unit of time in that frame of reference.

When it is said that, to a <em>stationary observer</em> you have a <em>speed of 9m/s</em>, it means that the observer "measures"  tha your position, in a moment, changes 9 m per second.

Since both you and your friend are sit still on the same spinning merry-go-round, neither of you will change positions with respect to the other, meaning that you will perceive that your friend will not move, from your frame of reference. That is, if you are isolated from the rest of the universe, and the merry-go-round continues spining uniformly, you cannot detect any movement of your friend, which means that from your frame of reference, the speed of your friend is zero.

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Answer:

1.28 m

Explanation:

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First of all we state the formula
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Therefore, the ratio between the surface area and the volume for the sphere will be:

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Equating the volume to the constant c, we will find the value of r.

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Substituting the value of r in the ration between surface area and volume, we get:

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\frac{4.83598}{c^{\frac{1}{3} } }

Hence, the ration between surface area and volume is \frac{4.83598}{c^{\frac{1}{3} } }

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\bold{ANSWER}

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