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alexgriva [62]
3 years ago
13

If Emily tries to jump over a narrow river at the speed of 6 m/s

Physics
1 answer:
Naddik [55]3 years ago
6 0

Answer:  0.6

Explanation: I'm doing the projectile motion problem solving and I was stuck but I guessed and choose that answer and it said I was correct.

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Which two statements are scientific claims?
slavikrds [6]

Answer:

c.an equation that can be used to accurately calculate the pull of gravity between two objects

Explanation:

umm ok for you

6 0
3 years ago
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Students are using the experimental setup shown in the image in which the two ends of a string are attached to a car and to a ha
AlekseyPX

The Newton's second law and kinematics allows to find the result of the error when placing the masses in the car is:

  • Acceleration decreases.
  • The plot of position vs. time squared is still linear, but the slope is less.

     

Newton's second law gives a relationship between the net force, mass and acceleration of the body

      F = ma

      a = \frac{F}{m}

Where F is the force, m the mass and the acceleration

 

Kinematics studies the motion of bodies, looking for relationships between position, velocity, and acceleration.

         x = v₀ t + ½ a t²

In the experiment, the position and time of the car are measured, starting from rest in each experiment.

        x = ½ a t²

Let's substitute

      x =  ½ ( \frac{F}{m} ) t²

This is the equation that the students should graph, a graph of the position versus time squared can be made to obtain a line.

The slope of the line is the acceleration of the car, which is related to the force that is the weight of the hanging mass.

When the student makes the mistake of placing the mass on the car, the acceleration decreases therefore in a graph the position values ​​are smaller for each time.

The linearity of the graph is maintained, but when calculating the slope it gives lower values.

In conclusion using Newton's second law and kinematics we can find the result of the error when placing the masses on the car is:

  • Acceleration decreases.
  • The plot of position vs. time squared is still linear, but the slope is less.

Learn more here: brainly.com/question/11298125

7 0
3 years ago
Read 2 more answers
Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol
sammy [17]
Grandparent and grandchild
7 0
3 years ago
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In the study of​ sound, one version of the law of tensions is:
Phantasy [73]

Answer:

F1 = 80

Explanation:

f1= f2 √ (F1/F2)

Where f1 = 300, f2 = 260 and F2 = 60

Putting in the above formula

300 = 260√(F1/60)

Dividing both sides by 260

=> 1.15 = √(F1/60)

Squaring both sides

=> 1.33 = F1/60

Multiplying both sides by 60

=> F1 = 80

5 0
3 years ago
A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w
Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

V_{E} = \frac{K*q}{r}

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

V_{1} + V_{2} = 0

K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0   (2)

By solving equation (2) for r₂:

r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m

                 

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

8 0
3 years ago
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