Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2. First we must determine the final velocity:
![v_{final}=v_{initial}+\frac{1}{2}at\\\\v_{final}=0+(7.4m/s^2)(2s)=34.8m/s](https://tex.z-dn.net/?f=v_%7Bfinal%7D%3Dv_%7Binitial%7D%2B%5Cfrac%7B1%7D%7B2%7Dat%5C%5C%5C%5Cv_%7Bfinal%7D%3D0%2B%287.4m%2Fs%5E2%29%282s%29%3D34.8m%2Fs)
Now we will determine the distance traveled:
![v_{final}^2=v_{initial}^2+2a \Delta x\\\\\Delta x = \frac{v_{final}^2}{2a} =\frac{(34.8)^2}{(2)(7.4)}=81.83 m](https://tex.z-dn.net/?f=v_%7Bfinal%7D%5E2%3Dv_%7Binitial%7D%5E2%2B2a%20%5CDelta%20x%5C%5C%5C%5C%5CDelta%20x%20%3D%20%5Cfrac%7Bv_%7Bfinal%7D%5E2%7D%7B2a%7D%20%3D%5Cfrac%7B%2834.8%29%5E2%7D%7B%282%29%287.4%29%7D%3D81.83%20m)
Therefore, the drag racer traveled 81.83 meters in 2 seconds.
Answer:
The acceleration will become zero
Explanation:
When the parachute of a falling soldier is opened the wide surface area decreases his velocity. This also translates to the drag force acting on the fallen soldier
The acceleration will become zero when the velocity of the fallen soldier is constant. This principle is the reason the parachute is used for safety reasons .
He's accelerating at 3 m/s² . That means his speed is increasing by 3 m/s every second.At the end of 8 seconds, his speed is (8 x 3 m/s) = 24 m/s .He's been moving south for the whole 8 seconds.So at the end of that time, his velocity is 24 m/s south .
Answer:
![\Delta E=2.87\times 10^6\ J](https://tex.z-dn.net/?f=%5CDelta%20E%3D2.87%5Ctimes%2010%5E6%5C%20J)
Explanation:
It is given that,
Depth of Death valley is 85 m below sea level, ![h_i=-85\ m](https://tex.z-dn.net/?f=h_i%3D-85%5C%20m)
The summit of nearby Mt. Whitney has an elevation of 4420 m, ![h_f=4420\ m](https://tex.z-dn.net/?f=h_f%3D4420%5C%20m)
Mass of the hiker, m = 65 kg
We need to find the change in potential energy. It is given by :
![\Delta E=mg(h_f-h_i)](https://tex.z-dn.net/?f=%5CDelta%20E%3Dmg%28h_f-h_i%29)
![\Delta E=65\times 9.8(4420-(-85))](https://tex.z-dn.net/?f=%5CDelta%20E%3D65%5Ctimes%209.8%284420-%28-85%29%29)
![\Delta E=2869685\ J](https://tex.z-dn.net/?f=%5CDelta%20E%3D2869685%5C%20J)
or
![\Delta E=2.87\times 10^6\ J](https://tex.z-dn.net/?f=%5CDelta%20E%3D2.87%5Ctimes%2010%5E6%5C%20J)
So, the change in potential energy of the hiker is
. Hence, this is the required solution.