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pychu [463]
3 years ago
9

What is the range of these data? 6,9,2,12,3,5,9​

Physics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

10

Explanation:

Subtract the smallest number from the biggest.

kifflom [539]3 years ago
4 0

Answer:10

Explanation:

Range is the difference between the highest and lowest number in a given set of numbers

Highest number=12 lowest number=2

Range=12-2

Range=10

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Given two vectors A⃗ =4.00i^+7.00j^ and B⃗ =5.00i^−2.00j^ , find the vector product A⃗ ×B⃗ (expressed in unit vectors).
Reptile [31]

Answer:

-43\hat{k}

Explanation:

given,

\vec{A} = 4 \hat{i} + 7 \hat{j}

\vec{B} = 5 \hat{i} - 2 \hat{j}

vector product \vec{A} \times \vec{B} = ?

\vec{A} \times \vec{B} = \begin{bmatrix}i & j & k\\ 4 & 7 &0 \\ 5 & -2 & 0\end{bmatrix}

now, expanding the vector

\vec{A} \times \vec{B}= \hat{k}(-2\times 4 - 7\times 5)

\vec{A} \times \vec{B}= -43\hat{k}

the vector product is equal to -43\hat{k}

4 0
4 years ago
A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the t
mars1129 [50]

<u>Answer:</u>

The acceleration of the plane and the time required to reach this speed is  (a)= 7.5 m/sec^2 and time(t) = 20 seconds  

<u>Explanation: </u>

Given data Initial velocity (V_i) = 0  

Final velocity (V_f) = 150 m/second

Distance (d) = 1500 m

We have the formula,  $\mathrm{V}_{\mathrm{f}}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 \mathrm{ad}$

which gives 150^2 = 0+2a(1500)    

22500 = 3000 a  

acceleration (a) = 7.5 m/s^2

$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at}$

150 = 7.5 t

t= 150/7.5 = 20

t = 20 seconds.  

5 0
3 years ago
Which bmi score listed below is considered over weight?
valentinak56 [21]
I don't see any answer choices, but if I remember correctly, the overweight BMI score is 20-22 and up. Probably 22 and up.
5 0
4 years ago
A negative charge of -0.550 m exerts an upward <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5868766e
almond37 [142]

Answer:

a. +10.9μC

b. 0.600N and downward

Explanation:

To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as

F=(kq₁q₂)/r²

since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as

q₂=Fr²/kq₁

q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)

q₂=0.054/4950

q₂=1.09*10⁻⁵c

q₂=10.9μC.

Hence the second charge is +10.9μC

b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N

8 0
4 years ago
Where are elements with few valence electrons found on the periodic table
Nimfa-mama [501]

Answer:

Valence electrons are the electrons present in the outermost shell of an atom. You can easily determine the number of valence electrons an atom can have by looking at its Group in the periodic table.

Explanation:

8 0
3 years ago
Read 2 more answers
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