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3 years ago

What is the range of these data? 6,9,2,12,3,5,9

Physics

2 answers:

k0ka [10]3 years ago

6 0

Answer:

Explanation:

Subtract the smallest number from the biggest.

kifflom [539]3 years ago

4 0

Answer:10

Explanation:

Range is the difference between the highest and lowest number in a given set of numbers

Highest number=12 lowest number=2

Range=12-2

Range=10

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Which quantities indicate a direction and a magnitude? Check all that apply.

Korvikt [17]

Answer:

Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. Although a vector has magnitude and direction, it does not have position.

Explanation:

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3 years ago

A 10kg object is 15 meters up a hill. Find its potential energy

Tema [17]

Answer:

Explanation:

Relative to an origin at the bottom of the hill,

PE = mgh = 10(9.8)(15) = 1470 J

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2 years ago

The force exerted by an electric charge at the origin on a charged particle at a point (x, y, z) with position vector r = x, y,

kap26 [50]

$W = K[ {\frac{1}{3} - \frac{1}{\sqrt{38} } ]$

Explanation:

The parametric representation of a line segment joining the points (a,b,c) and (l,m,n) is

r(t) = (1-t) . (a,b,c) + t . (l, m, n) where t ∈ |0, 1|

So, the parametric representation of a line segment joining the points (3,0,0) and (3,2,5) is

r(t) = (1 - t) . (3,0,0) + t . (3,2,5) where t ∈ |0, 1|

r(t) = (3(1 - t), 0, 0) + (3t, 2t, 5t) where t ∈ |0, 1|

r(t) = (3, 2t, 5t)

Given:

$F(x, y, z) = \frac{Kr}{|r|^3} \\\\F(x, y, z) = \frac{K}{(x^2 + y^2 + z^2)^3^/^2} (x, y, z)\\\\F(r(t)) = \frac{K}{(3^2 + (2t)^2 + (5t)^2)^3^/^2} (3, 2t, 5t)\\\\F(r(t)) = \frac{K}{(9 + 29t^2)^3^/^2} (3, 2t, 5t)$

dr = (0, 2, 5) dt

$Work = \int\limits^1_0 {F} \, dr$

$W = \int\limits^1_0 {\frac{K}{(9 + 29t^2)^3^/^2} } (3, 2t, 5t) . (0, 2, 5)\, dt\\ \\ = \int\limits^1_0 {\frac{K ( 4t + 25t)}{(9 + 29t^2)^3^/^2} } \, dt\\\\\\$

$W = \frac{1}{2}\int\limits^1_0 {\frac{K(29t)}{(9 + 29t^2)^3^/^2} } \, dt \\ \\$

Substitute = 9 + 29t² = u, 92tdt = du

Limit changes from 0→1 to 9 → 38

$W = \frac{K}{2} \int\limits^3_9 {\frac{du}{u^3^/^2} } \,\\\\$

On solving this, we get:

$W = K[ {\frac{1}{3} - \frac{1}{\sqrt{38} } ]$

Therefore, work done is $W = K[ {\frac{1}{3} - \frac{1}{\sqrt{38} } ]$

5 0

3 years ago

If the current throught a 6 Ω resistor is 7 A, what is the power absorbed by the resistor? Answer to the nearest 1 W.

Stells [14]

Answer:

294 W

Explanation:

Electrical power: This can be defined as the rate at which electrical energy is used or dissipated. The S.I unit of electrical power is Watt(W).

The expression of electrical power is given as,

P = I²R................... Equation 1

Where P = power, I = current, R = Resistance.

Given: I = 7 A, R = 6 Ω

Substitute into equation 1

P = (7)²(6)

P = 294 W.

Hence the power power absorbed by the resistor is 294 W

3 0

3 years ago

Read 2 more answers

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

olga_2 [115]

D. Mass equals weight times acceleration due to gravity.

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5 0

3 years ago

What is the range of these data? 6,9,2,12,3,5,9​

What is the range of these data? 6,9,2,12,3,5,9