1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ohaa [14]
3 years ago
8

Two radioactive nuclei A and B are present in equal numbers to begin with. Three days later, there are 4.04 times as many A nucl

ei as there are B nuclei. The half-life of species B is 1.37 days. Find the half-life of species A (in days).
Physics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

The half-life of A is 17.1 days.

Explanation:

Hi there!

The half-life of B is 1.73 days.

Let´s write the elapsed time (3 days) in terms of half-lives of B:

1.37 days = 1 half-life B

3 days = (3 days · 1 half-life B / 1.37 days) = 2.19 half-lives B.

After 3 days, the amount of A in terms of B is the following:

A = 4.04 B

The amount of B after 3 days can be expressed in terms of the initial amount of B (B0) and the number of half-lives (n):

B after n half-lives = B0 / 2ⁿ

Then after 2.19 half-lives:

B = B0 /2^(2.19)

In the same way, the amount of A can also be expressed in terms of the initial amount and the number of half-lives:

A = A0 / 2ⁿ

Replacing A and B in the equation:

A = 4.04 B

A0 / 2ⁿ = 4.04 · B0 / 2^(2.19)

Since A0 = B0

A0 / 2ⁿ = 4.04 · A0 / 2^(2.19)

Dividing by A0:

1/2ⁿ = 4.04 / 2^(2.19)

Multipliying by 2ⁿ and dividing by  4.04 / 2^(2.19):

2^(2.19) / 4.04 = 2ⁿ

Apply ln to both sides of the equation:

ln( 2^(2.19) / 4.04) = n ln(2)

n = ln( 2^(2.19) / 4.04) / ln(2)

n = 0.1756

Then, if 3 days is 0.1756 half-lives of A, 1 half-life of A will be:

1 half-life ·(3 days / 0.1756 half-lives) = 17.1 days

The half-life of A is 17.1 days.

You might be interested in
Which changes in an electric motor will make the motor stronger? select 3 options. using a stronger permanent magnet using a wea
Masja [62]

1. Using Strong Permanent. 2. increasing the current. 3. Decreasing the space between Magnets

Explanation:

Brainiest

4 0
2 years ago
A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
Suppose there are 100,000 atoms of a radioactive substance that has a ½ life of 10 minutes. How many atoms will remain after 40
dezoksy [38]

Answer:

c. 12,500

Explanation:

Original number of atoms = 100,000 atoms

Half- life  = 10min

Unknown:

The number of atoms that will remain after 10min  = ?

Solution:

The half - life is the time taken for half of a radioactive substance to decay by half.

    Time taken        Number of atom   half life

           10min             100000                   _

           20min             50000                    1

           30min             25000                    2

           40min              12500                     3

6 0
2 years ago
PLEASE HELP ASAP!!!!!!!!!!
Marianna [84]
Hey,


I think the answer's are 1,3


Hope this helpss

~Girlygir101~
7 0
3 years ago
A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later,
iris [78.8K]

Answer:

The work done by gravity is 4.975 \: Joules

Explanation:

The data given in the question is :

Mass is 0.245 kg

Height from ground is 2.07 m

As we know , the work done is state function , it depends on initial and final position not on the path followed.

So, work done by gravity = change in potential energy

Work done = Initial potential energy - final potential energy

Insert values from question

Work done = mass \times gravity \times (change \: in \: height)

Work done = 0.245 kg \times 9.81 m/s^{2} \times 2.07 m

So, work done = 4.975 Joules

Hence the work done by gravity is 4.975 \: Joules

3 0
3 years ago
Other questions:
  • When the voltage is high, 100v, how does the filament appear?
    13·1 answer
  • A 0.500-nm x-ray photon is deected through 134 in a Compton scattering event. At what angle (with respect to the incident beam)
    12·1 answer
  • When an object experiences uniform circular motion the direction of the net force is?
    14·1 answer
  • No physical processes have ever been demonstrated which provide a mechanism for the universe to assemble itself.
    14·2 answers
  • How much work is accomplished when a force of 400 N pushes a box across the floor for a distance of 10 meters?
    14·1 answer
  • 6. A stomp rocket takes 1.5 seconds to reach its maximum height
    8·1 answer
  • Which of the following is not supported by reliable evidence?
    12·2 answers
  • The heat generated by a stove element varies directly as the square of the voltage and inversely as the resistance. If the volta
    7·1 answer
  • Pilots can be tested for the stresses of flying high-speed jets in a whirling "human centrifuge," which takes 1.2min to turn thr
    11·2 answers
  • Classify the waves as being mechanical or electromagnetic.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!