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zaharov [31]
2 years ago
9

HELP ASAP PLS!!! when you see a full moon, what type of tides do you expect there to be?

Physics
1 answer:
EastWind [94]2 years ago
3 0

Answer:

<u><em>Spring High Tide</em></u>

<em>When the moon is full or new, the gravitational pull of the moon and sun are combined. At these times, the high tides are very high and the low tides are very low. </em>

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A particle is projected with velocity v0 directly up a slope which makes an angle α with the horizontal. Assume frictionless mot
Nikolay [14]

Answer:

a)T total = 2*Voy/(g*sin( α ))

b)α = 0º ,  T total≅∞ (the particle, goes away horizontally indefinitely)

α = 90º,  T total=2*Voy/g

Explanation:

  • Velocity in the Y axis:

Voy=Vo*sinα

  • Time to reach the maximal height :

Kinematics equation: Vfy=Voy-at

a=g*sinα ;  g is gravity

if Vfy=0 ⇒ t=T ; time to reach the maximal height

so:

0=Voy-g*sin( α )*T

T=Voy/(g*sin( α ))

  • Time required to return to the starting point:

After the object reaches its maximum height, the object descends to the starting point, the time it descends is the same as the time it rises.

So T total= 2T = 2*Voy/(g*sin( α ))

  • α = 0º , sinα=0

The particle goes totally horizontal, goes away indefinitely

T total= 2*Voy/(g*sin( α )) ≅∞

  • α = 90º, sinα=1

T total=2*Voy/g

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3 years ago
Calculate the average linear momentum of a particle described by the following wavefunctions: (a) eikx, (b) cos kx, (c) e−ax2 ,
Maksim231197 [3]

Answer:

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Explanation:

In quantum mechanics the moment operator is given by

              p = - i h’  d φ / dx

             h’= h / 2π

We apply this equation to the given wave functions

a)  φ = e^{ikx}

        .d φ dx = i k e^{ikx}

We replace

        p = h’ k e^{ikx}

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The exponential is a sine and cosine function, so its measured value is zero, so the average moment is zero

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b) φ = cos kx

           p = h’ k sen kx

The average sine function is zero,

          p = 0

c) φ = e^{-ax^{2} }

         d φ / dx = -a 2x  e^{-ax^{2} }

         .p = i a g ’2x  e^{-ax^{2} }

       The average moment is

         p = (p₂ + p₁) / 2

         p = i a h ’(-∞ + ∞)

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