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zalisa [80]
3 years ago
7

A table tennis ball with a mass of 0.003kg and soccer with a mass of 0.43 kg. are both set in motion at 16 m"s. Calculate and co

mpare the momenta of both balls.
Physics
2 answers:
Aliun [14]3 years ago
7 0

Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ) I use the subscript "t" for tennis.  Momentum of Soccer ball Ps= 0.43 x 13m/s = (      km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise  the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.

Mashcka [7]3 years ago
5 0

Answer:

\texttt{Ration of moment of soccer ball to table tennis ball}=\frac{6.88}{0.048}=143.33

Explanation:

Linear momentum is product of mass and velocity.

Mass of table tennis ball = 0.003 kg

Mass of table soccer ball = 0.43 kg

Velocity of both balls = 16 m/s

Momentum of tennis ball = 0.003 x 16 = 0.048 kgm/s

Momentum of soccer ball = 0.43 x 16 = 6.88 kgm/s

\texttt{Ration of moment of soccer ball to table tennis ball}=\frac{6.88}{0.048}=143.33

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Answer:

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Explanation:

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u = 0

Therefore, the change in speed is:

\Delta v = v-u=6-0 = 6 m/s

4 0
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kobusy [5.1K]

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juin [17]
Answer: c




Explanation:

Analytical methods

3 0
3 years ago
8
Doss [256]

Answer:

The resultant velocity is <u>169.71 km/h at angle of 45° measured clockwise with the x-axis</u> or the east-west line.

Explanation:

Considering west direction along negative x-axis and north direction along  positive y-axis

Given:

The car travels at a speed of 120 km/h in the west direction.

The car then travels at the same speed in the north direction.

Now, considering the given directions, the velocities are given as:

Velocity in west direction is, \overrightarrow{v_1}=-120\ \vec{i}

Velocity in north direction is, \overrightarrow{v_2}=120\ \vec{j}

Now, since v_1\ and\ v_2 are perpendicular to each other, their resultant magnitude is given as:

|\overrightarrow{v_{res}}|=\sqrt{|\overrightarrow{v_1}|^2+|\overrightarrow{v_2}|^2}

Plug in the given values and solve for the magnitude of the resultant.This gives,

|\overrightarrow{v_{res}}|=\sqrt{(120)^2+(120)^2}\\\\|\overrightarrow{v_{res}}|=120\sqrt{2} = 169.71\ km/h

Let the angle made by the resultant be 'x' degree with the east-west line or the x-axis.

So, the direction is given as:

x=\tan^{-1}(\frac{|v_2|}{|v_1|})\\\\x=\tan^{-1}(\frac{120}{-120})=\tan^{-1}(-1)=-45\ deg(clockwise\ angle\ with\ the\ x-axis)

Therefore, the resultant velocity is 169.71 km/h at angle of 45° measured clockwise with the x-axis or the east-west line.

4 0
3 years ago
What can always be said about a negatively-charged ion?
KiRa [710]

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Explanation:

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Then the correct option is:

A negatively-charged ion always has more electrons than protons

5 0
3 years ago
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