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zalisa [80]
3 years ago
7

A table tennis ball with a mass of 0.003kg and soccer with a mass of 0.43 kg. are both set in motion at 16 m"s. Calculate and co

mpare the momenta of both balls.
Physics
2 answers:
Aliun [14]3 years ago
7 0

Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ) I use the subscript "t" for tennis.  Momentum of Soccer ball Ps= 0.43 x 13m/s = (      km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise  the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.

Mashcka [7]3 years ago
5 0

Answer:

\texttt{Ration of moment of soccer ball to table tennis ball}=\frac{6.88}{0.048}=143.33

Explanation:

Linear momentum is product of mass and velocity.

Mass of table tennis ball = 0.003 kg

Mass of table soccer ball = 0.43 kg

Velocity of both balls = 16 m/s

Momentum of tennis ball = 0.003 x 16 = 0.048 kgm/s

Momentum of soccer ball = 0.43 x 16 = 6.88 kgm/s

\texttt{Ration of moment of soccer ball to table tennis ball}=\frac{6.88}{0.048}=143.33

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grin007 [14]

Answer

given,

mass of the rod = 1.50 Kg

length of rod = 0.85 m

rotational velocity = 5060 rev/min

now calculating the rotational inertia of the system.

I = m L^2        

where L is the length of road, we will take whole length of rod because mass is at  the end of it.      

I = 1.5 \times 0.85^2  

I = 1.084 kg.m²                        

hence, the rotational inertia the system is equal to I = 1.084 kg.m²

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3 years ago
At one instant, a 17.0-kg sled is moving over a horizontal surface of snow at 4.10 m/s. After 6.15 s has elapsed, the sled stops
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Answer:

force = 11.33 kg-m/s^{2}

Explanation:

given data:

sled mass = 17.0 kg

inital velocity (U) = 4.10 m/s

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Initial momentum of sledge is

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F = \frac{69.7-0}{6.15}= 11.33[tex]kg-m/s^{2}[/tex]

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