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Hi there!
I believe it looks like this.
At positions A, G kinetic energy is maximum.
At position D, potential energy is maximum.
Hope this helps! ☺♥
The cart travelled a distance of 14.4 m
Explanation:
The work done by a force when pushing an object is given by:

where:
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and the displacement
In this problem we have:
W = 157 J is the work done on the cart
F = 10.9 N is the magnitude of the force
, assuming the force is applied parallel to the motion of the cart
Therefore we can solve for d to find the distance travelled by the cart:

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Answer: FR=2.330kN
Explanation:
Write down x and y components.
Fx= FSin30°
Fy= FCos30°
Choose the forces acting up and right as positive.
∑(FR) =∑(Fx )
(FR) x= 5-Fsin30°= 5-0.5F
(FR) y= Fcos30°-4= 0.8660-F
Use Pythagoras theorem
F2R= √F2-11.93F+41
Differentiate both sides
2FRdFR/dF= 2F- 11.93
Set dFR/dF to 0
2F= 11.93
F= 5.964kN
Substitute value back into FR
FR= √F2(F square) - 11.93F + 41
FR=√(5.964)(5.964)-11.93(5.964)+41
FR= 2.330kN
The minimum force is 2.330kN
Answer:
Check below for the answers and explanations.
Explanation:
Note: You did not provide the diagram you mentioned but I will explain to you the sequence of events that take place as a fluid cools. I believe you can apply this to the particular diagram that you have.
Sequence of events that take place as a fluid cools down:
- There is a reduction in the temperature of the fluid
- The speed of movement of the molecules will reduce
- Since there is a reduction in speed, the Kinetic Energy also reduces. KE = 1/2 mv²
- The density of the fluid will increase as the temperature decreases
- The molecules will be closer to each other as opposed to in a gas where there is collision of molecules