Question
What was the initial momentum of the bullet before collision?
Answer:
10 Kg.m/s
Explanation:
Momentum is a product of velocity of an object in m/s and its mass in kgs hence numerically expressed as p=mv where p is momentum, v is velocity and m is mass. Substituting m for 0.2 kg and v for 50 m/s then p=0.2*50=10 kg.m/s
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
Speed = (distance covered) / (time to cover the distance)
= ( 8.45 km) / (0.65 hr)
= (8.45 / 0.65) km/hr
= 13 km/hr
The angle at which the sunlight received at a location on Earth spread out over the largest area is 10°. Last option is correct.
<h3>What is sunlight?</h3>
The light coming from the Sun reaching the Earth's surface is called as Sunlight.
When the sun is overhead, the intensity is high because sun's rays are perpendicular to the earth's surface, so the energy spreads over a small area and the heat is too high in that region.
When, the angle is smaller, the sunlight will spread out over a larger area.
Thus, at 10° the sunlight received at a location on Earth spread out over the largest area. Last option is correct.
Learn more about Sunlight.
brainly.com/question/23504828
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Answer:
AT
Explanation:
Dimensions of current = A
Dimensions of time = T
Current = Charge / time
Therefore Charge = Current × time
[Charge] = [Current] × [time]
= AT
