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Colt1911 [192]
3 years ago
6

What charge does an object have if it has an excess of electrons?

Physics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

negative charge

Explanation:

On an atomic scale, those are called "ions", and negatively charged ions are called anions.

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A floating ice block is pushed through a displacement d = (23 m) i - (9 m) j along a straight embankment by rushing water, which
Sav [38]

Answer:

Work = 5941 J

Explanation:

As we know that work done is given by the equation

W = F. d

here we know that

F  = (200 N)\hat i - (149 N) \hat j

also we have

d = (23m) \hat i - (9 m)\hat j

now from above formula we have

W = (200 N\hat i - 149 N \hat j).(23 m\hat i - 9m \hat j)

W = 5941 J

3 0
3 years ago
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Select all of the mixtures:<br> oxygen<br> gold<br> trail mix<br> soup <br> air
Alexxandr [17]

Answer:

trail mix, soup, and gold

hope this helps

have a good day :)

Explanation:

6 0
3 years ago
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The average distance from the sun to Pluto is approximately 6.10 × 109 km. How long does it take light from 
Scorpion4ik [409]
V= \frac{S}{t}
t= \frac{S}{V}<u />
t= \frac{S}{c}
t= \frac{6.1*10^{12}}{299792458}
t=20347.4098071s

It takes 20347.4098071s for light from the sun to reach Pluto.
The 6.1*10^9 is replaced by 6.1*10^12 on line 4 because we convert the distance from km to m. 
c = speed of light. If a different value was given in the previous question then use that instead of the value I used to do the final calculation.
3 0
3 years ago
What is an ellipse? ​
Rzqust [24]

Answer:An ellipse is a closed curve consisting of points whose distances from each of two fixed points (foci) all add up to the same value .

Explanation:

6 0
3 years ago
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Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed
Ivanshal [37]

Answer:

Part a)

f_w = f_g = 4.57 \times 10^{14} Hz

Part b)

\lambda_w = 492 nm

\lambda_g = 437.3 nm

Part c)

v_w = 2.25 \times 10^8 m/s

v_g = 2.0 \times 10^8 m/s

Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

f = \frac{v}{\lambda}

f = \frac{3 \times 10^8}{656 \times 10^{-9}}

f = 4.57 \times 10^{14} Hz

Part b)

As we know that the refractive index of water is given as

\mu_w = 4/3

so the wavelength in the water medium is given as

\lambda_w = \frac{\lambda}{\mu_w}

\lambda_w = \frac{656 nm}{4/3}

\lambda_w = 492 nm

Similarly the refractive index of glass is given as

\mu_w = 3/2

so the wavelength in the glass medium is given as

\lambda_g = \frac{\lambda}{\mu_g}

\lambda_g = \frac{656 nm}{3/2}

\lambda_g = 437.3 nm

Part c)

Speed of the wave in water is given as

v_w = \frac{c}{\mu_w}

v_w = \frac{3 \times 10^8}{4/3}

v_w = 2.25 \times 10^8 m/s

Speed of the wave in glass is given as

v_g = \frac{c}{\mu_g}

v_g = \frac{3 \times 10^8}{3/2}

v_g = 2 \times 10^8 m/s

4 0
3 years ago
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