Answer:
Explanation:
In this case we shall calculate rate of change of flux in the coli to calculate induced emf .
Flux through the coil = no of turns x area x magnetic field perpendicular to it
=34 x 2.25 x (3.95 )²x 10⁻⁴ Weber
= 1193.4 x 10⁻⁴Weber
Final flux through the coil after turn by 90°
= 1193.4 x 10⁻⁴ cos 90 ° =0
Change of flux
= 1193.4 x 10⁻⁴ weber.
Time taken = 0.335 s .
Average emf= Rate of change of flux
= change in flux / time
=1193.4 x 10⁻⁴ / .335
= 3562.4 x 10⁻⁴
356.24 x 10⁻³
=356.24 mV.
Current induced = emf induced / resistance
= 356.24/.780
= 456.71 mA.
1110 atm
Let's start by calculating how many cm deep is 36,000 feet.
36000 ft * 12 in/ft * 2.54 cm/in = 1097280 cm
Now calculate how much a column of water 1 cm square and that tall would mass.
1097280 cm * 1.04 g/cm^3 = 1141171.2 g/cm^2
We now have a number using g/cm^2 as it's unit and we desire a unit of Pascals ( kg/(m*s^2) ).
It's pretty obvious how to convert from g to kg. But going from cm^2 to m is problematical. Additionally, the s^2 value is also a problem since nothing in the value has seconds as an unit. This indicates that a value has been omitted. We need something with a s^2 term and an additional length term. And what pops into mind is gravitational acceleration which is m/s^2. So let's multiply that in after getting that cm^2 term into m^2 and the g term into kg.
1141171.2 g/cm^2 / 1000 g/kg * 100 cm/m * 100 cm/m = 11411712 kg/m^2
11411712 kg/m^2 * 9.8 m/s^2 = 111834777.6 kg/(m*s^2) = 111834777.6 Pascals
Now to convert to atm
111834777.6 Pa / 1.01x10^5 Pa/atm = 1107.2750 atm
Now we gotta add in the 1 atm that the atmosphere actually provides (but if you look closely, you'll realize that it won't affect the final result).
1107.274 atm + 1 atm = 1108.274 atm
And finally, round to 3 significant figures since that's the accuracy of our data, giving 1110 atm.
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