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Aleks04 [339]
3 years ago
5

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.400 s to p

ass from the top to the bottom of this window, which is 2.10 m high.
Physics
1 answer:
Rudiy273 years ago
4 0

Answer:

0.55 m

Explanation:

Parameters given:

Time taken to pass from the top of the window to the bottom = 0.4 s

Height of the window = 2.10 m

Given that we know the time taken for the flowerpot to fall the height of the window, we can find the initial velocity of the pot. Using one of Newton's equations of motion:

S = u*t + 0.5*g*(t^2)

Given that

g = +9.8m/s^2,

S = 2.1 m

t = 0.4 s

=> 2.1 = 0 4*u + (0.5 * 9.8 * 0.4 * 0.4)

2.1 = 0.4u + 0.784

=> 0.4u = 1.316

u = 3.29 m/s

We know that the flowerpot fell from a window above, hence, the final velocity of its fall from above is equal to the initial velocity of when it starts falling from top of the window below.

Using another equation of motion, we have that:

v^2 = u^2 + 2gs

Where

s = height of the window above to the top of the window below

v = 3.29 m/s

u = 0 m/s

3.29^2 = 0 + 2*9.8*s

10.82 = 19.6s

=> s = 0.55 m

Hence, the top of the window above is 0.55m far from the top of the window below.

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I'm not sure if you're supposed to convert the seconds to time.
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3 years ago
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A compass in a magnetic field will line up __________.
Klio2033 [76]

Answer:

Option c

Explanation:

Magnetic field lines form loops starting from north pole to south pole outside the magnet and from south pole to north pole inside the magnet.

Thus the field is such that it is directed outwards from the North pole and directed inwards to the South pole of the magnet.

A compass in a magnetic field will will comply with the magnet's North pole directing towards the magnetic field.

4 0
3 years ago
What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o
leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,  

d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}

This value can be used to determine the time for the pellet through the barrel:

t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s

Finally, we can use the above to calculate the force:

F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N



8 0
3 years ago
A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored, how high (in m) would
motikmotik

Then the maximum height of the catapult will be 69.78 meters.

<h3>What is kinematics?</h3>

The study of motion without considering the mass and the cause of the motion. The equation of motion is given below.

v = u + at

s = ut + (1/2)at²

v² = u² + 2as

A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored.

a = - 9.81 m/s²

u = 37 m/s

v = 0

s = h

Then the maximum height of the catapult will be given by the third equation.

v² = u² + 2as

0² = 37² - 2 × 9.81 × h

h = 37² / (2 × 9.81)

h = 69.78 meters

Then the maximum height of the catapult will be 69.78 meters.

More about the kinematics link is given below.

brainly.com/question/7590442

#SPJ1

4 0
1 year ago
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