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bixtya [17]
3 years ago
7

What would be the saturation concentration (mole/L) of oxygen (O2) in a river in winter when the air temperature is 0°C if the H

enry's law constant at this temperature is 2.28 × 10-3 mole/L-atm? What would the answer be in units of mg/L?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
7 0

20.21*10^-4 mg/L is the concentration.

Explanation:

Given:  

Pressure=1 atm.

Temperature=  0 degrees

Volume percent of air is 21%

Henry's Law constant K = 2.28 x 10^-3 mole/L-atm

The partial pressure of oxygen is 0.21 atm.

By Henry's law:

Concentration= K X Partial pressure

                        =  2.28*10^-3 *0.21

                          =  4.79*10^-4 moles/litre

Since, at STP 1 mole of oxygen occupies volume of 22.4L

concentration =mass/volume

     mass                  =  4.79*10^-4-4*22.4

                                 = 20.21*10^-4 mg

    20.21*10^-4 mg/L is the concentration.

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The elements in Groups 1 AU) and 7A(17) are all quite reactive. What is a major difference between them?
Yuliya22 [10]

Explanation:

Elements of group 1A are known as alkali metals. Elements of this group are lithium, sodium, potassium, rubidium, cesium, and francium.

All these elements are metals and every element of this group has 1 valence electron. So, in order to attain stability they will readily lose their valence electron.

Hence, elements of group 1A are very reactive.

On the other hand, elements of group 7A are also known as halogen group. Elements of this group are fluorine, chlorine, bromine, iodine, and astatine.

All these elements are non-metals and every element of this group has 7 valence electrons. So, in order to completely fill their octet these elements gain 1 electron from a donor atom.

Therefore, these elements are alo reactive in nature.

But the major difference between elements of group 1A and group 7A is that elements of group 1A are metals but elements of group 7A are non-metals.    

8 0
3 years ago
Help me please i need this aaaaaaaaa <3
mylen [45]
Can someone help me out too? , on my question?
4 0
3 years ago
Read 2 more answers
30
ollegr [7]

Answer:

The balanced equation is given below:

SiO2 + 4HF —> SiF4 + 2H2O

The coefficients are 1, 4, 1, 2

Explanation:

The equation for the reaction is given below:

SiO2 + HF —> SiF4 + H2O

The above equation can be balance by as follow:

There are 4 atoms of F on the right side and 1 atom on the left side. It can be balance by putting 4 in front of HF as shown below:

SiO2 + 4HF —> SiF4 + H2O

Therefore are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

SiO2 + 4HF —> SiF4 + 2H2O

Now the equation is balanced.

4 0
3 years ago
Gina is driving her car down the street. She has a teddy bear sitting on the back seat. A dog runs in front of Gina's car, so sh
BartSMP [9]

objects in motion tend to stay in motion unless acted upon by an outside force.

5 0
3 years ago
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How many moles are in 5.60 x 10^23 atoms of Na? How many moles of H2 can be formed from this amount of Na?
alisha [4.7K]

Answer:

\large \boxed{\text{A. 0.930 mol Na; B. 0.465 mol of H}_{2}}

Explanation:

A. Moles of Na

1 mol Na atoms = 5.60 × 10²³ atoms of Na

\text{Moles of Na } = 5.60 \times 10^{23} \text{ atoms Na} \times \dfrac{\text{1 mol Na}}{6.022 \times 10^{23}\text{ atoms Na}}\\\\= \text{0.930 mol Na}\\\text{There are $\large \boxed{\textbf{0.930 mol Na}}$ in 5.60 $\times 10^{23}$ atoms of Na.}

B. Moles of hydrogen

You haven't given  the equation for the reaction. However, we can write an equation

                 2Na + 2HX ⟶ 2NaX+ H₂

n/mol:  0.930  

1 mol of H₂ is formed from 2 mol of Na

\text{Moles of H}_{2} = \text{0.930 mol Na} \times \dfrac{\text{1 mol H}_{2}}{\text{2 mol Na}} = \textbf{0.465 mol H}_{2}\\\\\text{You can form $\large\boxed{\textbf{0.465 mol of H}_{2}}$}

5 0
3 years ago
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