Answer:
If you're indoors, stay inside. If you're outside, stay outside. If you're indoors, stand against a wall near the center of the building, stand in a doorway, or crawl under heavy furniture (a desk or table). Stay away from windows and outside doors.
Answer:
Neither arre correct
Explanation:
Neither Anya nor Braden are correct. This is because if you use 90 degrees, 180 degrees, or even 270 degrees you will not get the exact image, which means that the image will not be found by just a rotation because there will be a curve in the image. You can solve it if you can do 90 degree rotation and translation.
Answer:
The pKa of the conjugate acid is 17.7
Explanation:
If hydrogen is removed from water, the equilibrium concentration of the conjugate acid according to the information given in the question becomes,
Kₐ = [OH⁻]/[H₂O]
Now, we determine the equivalent pKa
pKa = -log[ka]
pKa = -log[100]
pKa = -2
Removal of hydrogen from water is reversible as shown below;
H₂O ⇄ OH⁻ + H⁺
15.7 -2
This reaction is reversible, and the difference in pKa = pKa[H₂O] - pKa[H⁺];
pKa of the conjugate acid = 15.7 - (-2) = 17.7
The pKa of the conjugate acid is 17.7
Answer:
fluorine
Explanation:
because it is at the top of the halogen group, which is the second to right group on the periodic table. With halogens, the higher an element is in the column, the more reactive it is. Halogens are reactive because the outer shells that orbit the nucleus lack electrons.
also because it has low dissociation energy and the valence bonding is seen close to the nucleus hence the attraction for a new electron is greater and can gain an extra electron more easily.-if ur in a higer grade u will understand this
Answer:
Q = 7.0
Q = kc. The reaction is in equilibrium
Explanation:
Based on the reaction:
Br₂ + Cl₂ ⇄ 2BrCl
Equilibrium constant of the reaction, kc, is the ratio of <em>equilibrium concentrations</em> products over reactants powered to its reaction coefficient:
Kc = [BrCl]² / [Br₂] [Cl₂] = 7.0
Now, reaction quotient, Q, is write as the same Kc but the concentrations are actual concentrations:
Q = [BrCl]² / [Br₂] [Cl₂]
Replacing:
Q = [0.00415M]² / [0.00366M] [0.000672M]
Q = 7.0
Now, as Q = Kc = 7.0, the reaction mixture is in equilibrium
