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pav-90 [236]
3 years ago
9

What is one use of the mineral gypsum?

Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

Explanation:

3

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Which statement describes an eletron
Vitek1552 [10]
An electron carries a negative power to the atom. in each atom, the amount of protons and electrons are usually evened out so the atom is stable. the electrons of an atom are also found on the outside ring of an atom, unlike protons and neutrons, which are inside the atom. glad to help! :)
4 0
3 years ago
Given the following balanced equation determine the amount of MgCl2 that can be produced from 65.0 grams of Mg. Mg + HCl -->
DedPeter [7]

Answer:

Mg + HCL --> MgCl2 + H2

mass 65.0 mass 257.26

RFM 24 RFM 95

moles 2.708 moles 2.708

Explanation:

mass of MgCl = 257.26 grams

4 0
3 years ago
A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to
Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure P_{1} = 1.03 atm = 104.325 K pa

Initial temperature T_{1} = 26 °c = 299 K

Initial volume V_{1} = 22.4 L

Final temperature T_{2} = 22 °c = 295 K  

Final pressure P_{2} = 0.81 atm = 82 K pa

We know that

\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }

Put all the values in above formula we get

\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}

V_{2} = 28.11 L

This is the final volume of the balloon.

8 0
3 years ago
Some forms of vitamin D, C₂₈H₄₄O, can be found in red meat. How many total atoms are in 5 molecules of C₂₈H₄₄O
MaRussiya [10]

Answer:

3.01 × 10^24 atoms of vitamin D

Explanation:

The number of atoms, molecules or ions present in a substance is given by the Avogadro's number which is 6.02 × 10^23.

Hence;

1 molecule of vitamin D contains 6.02 ×10^23 atoms

5 molecules of vitamin D contains 5 × 6.02 ×10^23/1

= 3.01 × 10^24 atoms of vitamin D

7 0
3 years ago
An atom of gold has a mass of 3.271 X 10-22 g. How many atoms of gold are in 5.00 g of gold? (Give your answer in scientific not
Kobotan [32]

Answer:

1.53 × 10²² atoms Ag

Explanation:

Step 1: Define conversions

3.271 × 10⁻²² g = 1 atom

Step 2: Use Dimensional Analysis

5.00 \hspace{3} g \hspace{3} Ag(\frac{1 \hspace{3} atom \hspace{3} Ag}{3.271(10)^{-22} \hspace{3} g \hspace{3} Ag} ) = 1.52858 × 10²² atoms Ag

Step 3: Simplify

We have 3 sig figs.

1.52858 × 10²² atoms Ag ≈ 1.53 × 10²² atoms Ag

5 0
3 years ago
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