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Luba_88 [7]
3 years ago
9

7th grade math! Proportionality and similar shapes

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0
6 is 5.5 because the length of GH is half of KL
svp [43]3 years ago
3 0

6 is 5.5 because the length of GH is half of KL

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Find the quotient. 12a^3p^4 ÷ -2a^2p
777dan777 [17]

Answer:

-(6ap³)

Step-by-step explanation:

We have to find the quotients of

\frac{12a^{3}p^{4}}{-2a^{2}p}

We take the common 2a² p from the numerator

= \frac{(6ap^{3}(2a^{2}p))}{(-2a^{2}p)}

= -(6ap³)

Therefore, the quotient after division will be -(6ap³)

4 0
3 years ago
What is the square root of -16?<br> е в<br> -87<br> 0 ООО<br> 8
Monica [59]

4i

i=\sqrt{-1}

\sqrt{-16}=\sqrt{-1}*4

\sqrt{-16}=i*4

4i

Hope this helps.

頑張って!

8 0
3 years ago
Please this is urgent fill in the blanks
Nutka1998 [239]

Answer:

b)

a)

a)

Step-by-step explanation:

hope this helps i havent done this in a while

4 0
3 years ago
The first 32 whole numbers are evenly spaced around the circumference of a circle. Which number will be opposite of 26?
Ludmilka [50]

Answer:

"10"

Step-by-step explanation:

This is rather thinking "pictorially". Picture it.

You can match it with a round clock that has numbers 1 - 12 written on it.

So,

32 and 16 would be opposite of each other [top and bottom]. And, 1 - 15 would be on right side and 17 - 31 would be on left side.

Now,

Going counter-clockwise from 32, 26 would be the 6th number. Going counter-clockwise from 16, 10 would be the 6th number.

Hence, they would be opposite of each other.

10 would be opposite of 26

6 0
3 years ago
Hi I would like to know how I can solve this problem.
murzikaleks [220]

The n-th term is

U_n = \dfrac14 n^2 (n+1)^2

so the 39th term is

U_{39} = \dfrac14 39^2 40^2 = \boxed{608,400}

Observe that

2^3 + 4^3 + 6^3 = 2^3 + 2^3\times2^3 + 2^3\times3^3 = 8\left(1^3+2^3+3^3)

which suggests that

V_n = 8U_n = \boxed{2n^2(n+1)^2}

3 0
2 years ago
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