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wariber [46]
3 years ago
12

Jax went to the vet and the scale reads 9 pounds. what does this mean?

Physics
1 answer:
makkiz [27]3 years ago
8 0

if jax is an animal it means it is under weight. and if its a human there severly anorexic

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What is the definition of work when net force is parallel to the distance?
goldfiish [28.3K]
Work in general is given by W=F·d where F is the force vector and d is the displacement vector.  The dot symbol is the dot product which is a measure of how parallel two vectors are.  It can be replaced by the cosine of the angle between the two vectors and the vectors replaced by their magnitudes.  If F and d are parallel then the angle is zero and the cosine is unity.  So in this case work can be defined as the product of the magnitudes of the force and distance:
W=Fd
6 0
3 years ago
If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th
olga55 [171]

Answer:

f1= -350cm or -3.5m

f2= 22.1cm or 0.221m

Explanation:

A person is nearsighted when the person's far point is less than infinity. A diverging lens is normally used to correct this eye defect. A diverging lens has a negative focal length as seen in the solution attached.

Farsightedness is when a person's near point is farther than 25cm. This eye defect is corrected using a converging lens. The focal length of a converging lens is positive. This is evident in the solution attached. The near point is also referred to as the least distance of distinct vision.

3 0
3 years ago
A drone is flying horizontally when it runs out of power and begins to free fall from 16 m. No drag. If it lands 40 m away (in t
marysya [2.9K]

Answer:

the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

Given;

height of fall, h = 16 m

horizontal distance, x = 40 m

The time to travel 16 m is calculated as;

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s

The horizontal velocity is calculated as;

v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s

Therefore, the horizontal velocity while it was falling is 22.1 m/s.

7 0
2 years ago
A 1000kg truck is moving at a velocity of 4m/s what is it's momentum?
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Answer:

4000 kg m/s

Explanation:

<u><em>p=mv</em></u>

  • p = momentum in kg m/s
  • m = mass in kg
  • v = velocity in m/s

substitute values into the formula above to get:

p=1000x4

<u><em>p=4000 kg m/s</em></u>

6 0
2 years ago
Apply Newton's first law to each of the following situations. In which situations can you conclude that the object is undergoing
Vsevolod [243]

You only list one situation, are there any more?

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3 years ago
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