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skad [1K]
4 years ago
6

What type of magnetism is generated when a current-carrying wire is wrapped around an iron core?

Physics
2 answers:
lakkis [162]4 years ago
5 0
A simple electromagnet consisting of a coil of insulated wire wrapped around an iron core<span>. A </span>core<span> of ferromagnetic material like </span>iron<span> serves to increase the magnetic field created. The strength of magnetic field </span>generated<span> is proportional to the amount of </span>current<span> through the winding.</span>
ahrayia [7]4 years ago
5 0

Answer: The correct answer is temporary magnetism.

Explanation:

Electromagnet is a temporary magnet. It has temporary magnetism. When an iron core is wrapped by using the current carrying wire. When current is switched off then it will lose its magnetism. If the current starts flowing in the wire then it will again gain its magnetism.

The strength of magnetic field  is proportional to the amount of current through the wire.

Therefore, the type of magnetism is temporary when a current carrying wire is wrapped around an iron core.

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A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be
Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, A=1\ cm^2=0.0001\ m^2

Resistivity of gold wire, \rho=2.8\times 10^{-8}\ \Omega-m

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

R=\rho \dfrac{l}{A}

l=\dfrac{RA}{\rho}

l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0
3 years ago
Radial tires generally give the best gas mileage. <br> a. true <br> b. false
Ilya [14]
I believe the correct answer is true. Radial tires generally give the best gas mileage. <span>The advantages of </span>radial tires<span> include longer tread life, better steering characteristics, and less rolling resistance, which increases </span><span>gas mileage. Hope this answers the question.</span>
4 0
4 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.
Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0
4 years ago
In order to create a charged object, you need to ________.
Brums [2.3K]
In order to create a charged object you need to transfer electrons either away or to the object by induction, conduction, or friction

Induction is without contact(like bringing a charged object to a electroscope charges the leaves at the bottom)
Conduction is with contact(like the previous answer, wore touching transfers the charge from a source to the object)
Friction(rubbing a balloon on wool)

7 0
3 years ago
What velocity in km/hr would it take to accelerate a 2 kg object to the same momentum of a 1500 kg object with a velocity of 1.6
Lynna [10]

Answer:

v = 4374 Km/h

Explanation:

Given that,

Mass of the smaller object, m = 2 Kg

Mass of the bigger object, M = 1500 Kg

Velocity of the bigger object, V = 1.62 m/s

Velocity of the smaller object, v = ?

The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula

                                p = mv  Kg m/s

To find the momentum of the bigger object, substitute M and V in the above equation

                                p = 1500 Kg x 1.62 m/s

                                   = 2430 Kg m/s

The velocity imparted to the small body to attain this momentum is given by the relation

                               v = p/m  m/s

                                   = 2430 Kg m/s  /  2 Kg

                                   = 1215 m/s

By converting the velocity to Km/h

                                v = 4374 km/h

Hence, the velocity of the 2 Kg object is v = 4374 km/h

6 0
3 years ago
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