Given:
density of air at inlet, 
density of air at inlet, 
Solution:
Now,
(1)
where
A = Area of cross section
= velocity of air at inlet
= velocity of air at outlet
Now, using eqn (1), we get:
= 1.14
% increase in velocity = 
=114%
which is 14% more
Therefore % increase in velocity is 14%
Answer: the contents of this container weighs 4905 kg.m/s²
Explanation:
Given that;
volume of a container V = 0.5 m³
we know that standard gravitational acceleration g = 9.81 m/s²
specific volume of liquid filled in the container v = 0.001 m³/kg
now we express the equation for weight of the container.
W = mg
W = (pV)g
W = Vg / ν
so we substitute
W = (0.5 m³)(9.81 m/s ) / 0.001 m³/kg
W = 4.905 / 0.001
W = 4905 kg.m/s²
Therefore, the contents of this container weighs 4905 kg.m/s²
Answer:
no se porque xD jajjakajajjajajajjaj
Answer:
it can occur in all waves because all wave have a frequency
Answer:
200000J
Explanation:
Here the 1000N÷m is given. It is the torque. Now torque is a type of force created when an object turns.so it is a force.
100kg crate is the mass of the object.
2m is the height.
So the equation to measure gravitational pot. Enrg. Is = mass x force x height
So 1000x100x2 gives us 200000J.
Thank you
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❤️❤️With love,
Joel X grader
