<span> The quantity that is determined by the distance moved and the force used is called work.
To determine the amount of work being done you would simply multiply the distance moved and the amount of force used.
HOPE THIS HELPS! ^_^</span>
To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.
Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by
![z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}](https://tex.z-dn.net/?f=z%20%3D%20%5Csum%5Climit_i%20e%5E%7B-%5Cfrac%7B%5Cepsilon_i%7D%7BK_0T%7D%7D)
Where,
energy of that state
k = Boltzmann's constant
T = Temperature
With our values we have that
T= 250K
![k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}](https://tex.z-dn.net/?f=k%20%3D%201.381%2A10%5E%7B23%7D%20m%5E2%20kg%20s%5E%7B-2%7D%20K%5E%7B-1%7D)
![\epsilon_1=0J](https://tex.z-dn.net/?f=%5Cepsilon_1%3D0J)
![\epsilon_2=1.6*10^{-21}J](https://tex.z-dn.net/?f=%5Cepsilon_2%3D1.6%2A10%5E%7B-21%7DJ)
![\epsilon_3=1.6*10^{-21}J](https://tex.z-dn.net/?f=%5Cepsilon_3%3D1.6%2A10%5E%7B-21%7DJ)
To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as
![\beta = \frac{1}{kT}](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20%5Cfrac%7B1%7D%7BkT%7D)
![\beta = \frac{1}{(1.381*10^{23} m^2)(250)}](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20%5Cfrac%7B1%7D%7B%281.381%2A10%5E%7B23%7D%20m%5E2%29%28250%29%7D)
![\beta = 2.9*10^{20}J](https://tex.z-dn.net/?f=%5Cbeta%20%3D%202.9%2A10%5E%7B20%7DJ)
Therefore the average energy would be,
![\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}](https://tex.z-dn.net/?f=%5Cbar%7B%5Cepsilon%7D%20%3D%5Cfrac%7B%5Csum%20%5Cepsilon_i%20e%5E%7B-%5Cbeta%20%5Cepsilon_i%7D%7D%7B%5Csum%20e%5E%7B-%5Cbeta%20%5Cepsilon_i%7D%7D)
Replacing with our values we have
![\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}](https://tex.z-dn.net/?f=%5Cbar%7B%5Cepsilon%7D%20%3D%20%5Cfrac%7B0e%5E%7B-0%7D%2B1.6%2A10%5E%7B-21%7D%2Ae%5E%7B-%5CBeta%281.6%2A10%5E%7B-21%7D%29%7D%2B1.6%2A10%5E%7B-2-1%7D%2Ae%5E%7B-%282.9%2A10%5E%7B20%7D%29%281.6%2A10%5E%7B-21%7D%29%7D%7D%7B1%2B2e%5E%7B-2.9%2A10%5E%7B20%7D%2A1.6%2A10%5E%7B-21%7D%7D%7D)
![\bar{\epsilon} = 0.9*10^{-22}J](https://tex.z-dn.net/?f=%5Cbar%7B%5Cepsilon%7D%20%3D%200.9%2A10%5E%7B-22%7DJ)
Therefore the average internal energy is ![\bar{\epsilon} = 0.9*10^{-22}J](https://tex.z-dn.net/?f=%5Cbar%7B%5Cepsilon%7D%20%3D%200.9%2A10%5E%7B-22%7DJ)
Answer:
Tortoise has the greatest momentum
Explanation:
Momentum of tourtise (p)=mass×velocity
=275×0.55
=151.25 kgm/s
Answer:
Explanation:
given that
mass = 10kg
distance = 4m
force = 50N
to calculate the workdone when the force is applied in the same direction of displacement
mathematically,
workdone = force × distance
Workdone = 50 × 4
workdone = 200 joules
2) to calculate the workdone at an angle of 30° with the displacement we apply the formula
workdone = force × distance × cos Ф
workdone = 50 × 4 × cos 30°
workdone = 200 × 0.866
workdone = 173 . 2 joules