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ratelena [41]
4 years ago
6

36 feet rounded to the nearest tenth of a foot

Mathematics
1 answer:
jek_recluse [69]4 years ago
4 0
I don't exactly understand what you're asking, 36 feet does not need to be rounded to the nearest tenth as it is a whole number. Do you mean rounded to 40? (As that would be the nearsest multiple of 10) I'm a bit lost, but hopefully that helps
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sammy [17]
Could it be Red Blue Blue Green Purple? Or Red Blue Green Grey Purple?
4 0
3 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
Example 1:
yawa3891 [41]

Answer:

Step-by-step explanation:

4 0
3 years ago
Find the solution to the equation 8x + 6 - 2x = 6x +5
Hunter-Best [27]
The answer is no solution. 
First you simplify both sides of the equation... Then you subtract 6x from both sides. And lastly you subtract 6 from both sides. Leaving you with no solutions.
4 0
4 years ago
Read 2 more answers
Solve 3/4x+1/4y=5 for y​
Sergeeva-Olga [200]

Answer:

y=3x+20

Step-by-step explanation:

So first, I don't like fractions so I would multiply the whole equation by 4. This will make the equation 3x+y=20. Then you have to isolate the y to find the answer so you should subtract 3x from both sides. This will make the equation look like this y=-3x+20. Therefore, y=3x+20

8 0
3 years ago
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