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expeople1 [14]
4 years ago
15

What is the midpoint between 3.82 and 3.81. please, I need major help with this

Mathematics
2 answers:
Ilya [14]4 years ago
8 0
I think your answer is 3.865
kicyunya [14]4 years ago
4 0
It's 3.815
Hope it helps you.
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The answer to question 24 please!
erica [24]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

  • Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;

  • Paul's distance east =  15 km × cos(37°) ≈ <u>11.98 km</u>

Pau's distance travelled in the south direction relative to the starting point

is given by the vertical distance travelled relative to the x-axis, which is

given as follows;

Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>

Learn more about bearings in trigonometry here:

brainly.com/question/23427938

5 0
2 years ago
IM IN DESPERATE NEED FOR HELP SOMEONE HURRRRYYY
LenaWriter [7]

Answer:

yes, triangle DEF is similar to triangle DBC, BC corresponds to EF, and angle DCB corresponds to angle F.

Step-by-step explanation:

Part A: Angle D is congruent to angle D by the reflexive property. Since line BC is parallel to line EF then angle DCB = angle DFE by corresponding angles.  Hence triangle DEF is similar to triangle DBS by the AA Similarity Postulate.

Part B: BC corresponds to EF because they are in the same order and the triangles listed DEF and DBC

Part C: Angle DCB corresponds to angle F since they are corresponding angles with the two given parallel lines BC and EF.

3 0
3 years ago
Sketch the graph that has an area of under the standard normal curve and to the left of the​ z-score. Then find the associated​
Anestetic [448]

The normal distribution is also known as the Gaussian distribution. The correct option is B, while the approx z-score is 0.31.

<h3>What is Normal Distribution?</h3>

The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data distant from the mean. The normal distribution will show as a bell curve on a graph.

Since the normal distribution is symmetrical about the mean. Therefore, the correct option is B, while the approx z-score is 0.31.

Learn more about Normal Distribution:

brainly.com/question/15103234

#SPJ1

4 0
2 years ago
Quadrilateral A’B’C’D’ is a dilation of quadrilateral ABCD about point P. Quadrilateral ABCD is shown. Side AB is labeled 5. Sid
Stolb23 [73]

Answer:  The correct option is (A) reduction.

Step-by-step explanation:  Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.

As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:

AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.

And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

A'B'=1\dfrac{1}{4}=\dfrac{5}{4}~\textup{units},~~B'C'=1~\textup{units},~~C'D'=2\dfrac{1}{2}=\dfrac{5}{2}~\textup{units},\\\\D'A'=1\dfrac{1}{2}=\dfrac{3}{2}~\textup{units}.

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.

Now, the scale factor is given by

S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}\\\\\\\Rightarrow S=\dfrac{A'B'}{AB}=\dfrac{\frac{5}{4}}{5}=\dfrac{5}{4\times5}=\dfrac{1}{4}

Since the scale factor is less than 1, so the dilation will be a reduction.

5 0
3 years ago
Read 2 more answers
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