Check the picture below.
make sure your calculator is in Degree mode.
For this, we need to know the length of the base at the time of interest. It will be
... A = (1/2)bh
... b = (2A)/h = 2(81 cm²)/(10.5 cm) = 108/7 cm
Differentiate the formula for area and plug in the given numbers.
... A = (1/2)bh
... A' = (1/2)(b'h +bh')
... 3.5 cm²/min = (1/2)(b'·(10.5 cm) + (108/7 cm)·(2.5 cm/min))
... 7 cm²/min = 10.5b' cm + 38 4/7 cm²/min . . . . simplify a bit
... -31 3/7 cm²/min = 10.5b' cm . . . . . . . . . . . . . . . subtract 38 4/7 cm²/min
... (-220/7 cm²/min)/(10.5 cm) = b' ≈ -3.0068 cm/min
The base is changing at about -3 cm/min.
The correct answer is A. 9/12 times 48.
Answer:
a=
Step-by-step explanation:
You are looking for <em>a </em>meaning <em>a </em>needs to be alone.
So subtract -3b+9c from both sides
14a=18+3b+9c
Then divided the right side by 14 to get<em> a</em> alone.
a=