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yaroslaw [1]
3 years ago
15

30.0L of helium gas into moles of helium gas.​

Chemistry
1 answer:
zepelin [54]3 years ago
3 0
<h3>Answer:</h3>

1.25 moles (R.T.P.) or 1.34 moles (S.T.P.)

<h3>Explanation:</h3>
  • 1 mole of a gas occupies a volume of 24 liters at room temperature and pressure (R.T.P.)
  • On the other hand, 1 mole of a gas will occupy 22.4 Liters at standard temperature and pressure (S.T.P.)

Therefore, at R.T.P.

30.0 Liters will be equivalent to;

= 30.0 L ÷ 24 L

= 1.25 moles

At S.T.P

30.0 Liters will be equivalent to;

= 30.0 L ÷ 22.4 L

= 1.34 moles

Thus, 30.0 L of helium gas are equivalent to 1.25 moles of He at R.T.P. and 1.34 moles at S.T.P.

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A West Virginia coal is burned at a rate of 8.02 kg/s. The coal has a sulfur content of 4.40 % and the bottom ash contains 2.80
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Answer: The annual emission rate of SO2 is 1.08 × 10^{7} kg/yr

Explanation:

  • The rate <em>r</em> at which the coal is been burnt is 8.02 kg/s.
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i.e., 4.4/100 × 8.02 = 0.353 kg/s. Which is equivalent to the rate at which the sulphur is been burnt.

  • Since the burning of sulphur oxidizes it to produce SO2, it follows that the non-oxidized portion of the sulphur will go with the bottom ash.

  • The bottom ash is said to contain 2.80 % of the input sulphur.

  • Hence the portion of the SO2 produced is 100 — 2.80 = 97.20 %.

  • The rate of the SO2 produced is percentage of SO2 × rate at high sulphur is been burnt.

  = 97.20/100 × 0.353 kg/s.

  = 0.343 kg/s.

  • To get the annual emission rate of SO2, we convert the kg/s into kg/yr.

1 kg/s = 1 kg/s × (60 × 60 × 24 × 365) s/yr

1 kg/s = 31536000 kg/yr

  • Therefore, 0.343 kg/s = 0.343 × 31536000 kg/yr

     = 10816848 kg/yr

     = 1.08 × 10^7 kg/yryr.

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This gas can be formed if a hydrogen bomb is detonated.
Levart [38]

Answer:

Helium.

Explanation:

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7 0
3 years ago
What's the answer ???
lesya692 [45]
The answer would be step three but not positive this is correct hope this helps
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ANSWER:

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~batmans wife dun dun dun...aka ~serenitybella

5 0
3 years ago
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