Answer:
The balanced equations for those dissociations are:
Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻ (aq)
H₂SO₄ (aq) → 2H⁺(aq) + SO₄⁻²(aq)
Explanation:
As a strong base, the barium hidroxide gives OH⁻ to the solution
As a strong acid, the sulfuric acid gives H⁺ to the solution
Ba(OH)₂, is a strong base so the dissociation is complete.
H₂SO₄ is considerd a strong acid, but only the first deprotonation is strong.
The second proton that is released, has a weak dissociation.
H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)
HSO₄⁻(aq) ⇄ H⁺ (aq) + SO₄⁻² (aq) Ka
Answer: 1.875 moles
Explanation:
2 NaN3(s) → 2 Na(s) + 3 N2(g)
From the equation above, Sodium azide has a chemical formula of NaN3 while nitrogen gas has a chemical formula of N2.
Therefore, If on decomposition
2 moles of NaN3 produce 3 moles of N2
1.25 mol of NaN3 produce Z moles of N2
To get the value of Z, cross multiply
Z x 2 moles = 3 moles x 1.25 moles
2 moles•Z = 3.75 moles²
Divide both sides by 2 moles
2 moles•Z/2 moles = 3.75 moles²/2 moles
Z = 1.875 moles
Thus, 1.875 moles of N2 are produced by the decomposition of 1.25 mol of sodium azide
Answer:
work = 3.45 Joules
Explanation:
Work from the 1st Law of Thermodynamics is PΔV in the equation of internal energy => ΔE = ΔH + PΔV.
Therefore, work = PΔV = 2.07atm·(2.334L - 0.666L) = 3.45 L·atm = 3.45 Joules
What is the question? lol