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3 years ago

All of the following increases the risk of getting HIV, Except which one?

Chemistry

2 answers:

olga55 [171]3 years ago

4 0

Answer:

always wear protection to lower the risks of diseases.

just olya [345]3 years ago

4 0

what are the options?

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A solution has [c6h5cooh] = 0.100 m and [ca(c6h5coo)2] = 0.200 m. ka = 6.3 × 10−5 for c6h5cooh. the solution volume is 5.00 l. w

Eddi Din [679]

6.8 is the pH of the solution after 10 ml of 5M NaOH is added.

Explanation:

Data given:

Molarity of C6H5CCOH = 0.100 M

molarity of ca(c6h5coo)2 = 0.2 M

Ka = 6.3 x 10^-5

first pH is calculated of the buffer solution

pH = pKa+ log 10 $\frac{[A-]}{[HA]}$

pKa = -log10[Ka]

pka = -log[6.3 x10^-5]

pKa = 4.200

putting the values to know pH of the buffer

pH = 4.200 + log 10 $\frac{0.2}{0.1}$

pH = 4.200 + 0.3

pH = 4.5 (when NaOH was not added, this is pH of buffer solution)

now the molarity of the solution is calculated after NaOH i.e Mbuffer is added

MbufferVbuffer = Mbase Vbase

putting the values in above equation:

Mbuffer = $\frac{MbaseVbase}{Vbuffer}$

= $\frac{5X10}{5000}$

= 0.01 M

molarity or [ A-] = 5M

pH = pKa+ log 10 $\frac{[A-]}{[HA]}$

pH = 4.200 + log 10 $\frac{5}{0.01}$

pH = 4.200+ 2.69

pH = 6.8

4 0

3 years ago

Read 2 more answers

Sort the examples based on whether they describe a physical change or a chemical reaction. growth of a seed into a seedling tarn

Pepsi [2]

Answer: I did the research myself since I couldn’t find the answers.

Physical change:

Wax melting from applied heat

Grinding wheat to make flour

Adding copper with gold to make jewelry

Chemical Reaction:

Growth of a seed into a seedling

Making caramel by burning sugar

Tarnishing of silver

Explanation:

Thanks google

4 0

3 years ago

Which element has 16 protons in its nucleus

maks197457 [2]

The element is Sulfur.

3 0

3 years ago

Read 2 more answers

One liter of air contains about 0.21 L of oxygen. When filled, the human lungs hold about 6.0 L of air. How much oxygen is in th

Pie

Simple 6L of air times the .21L of O2 = 1.26

3 0

3 years ago

The rate constants of some reactions double with every 10 degree rise in temperature. Assume that a reaction takes place at 271

AfilCa [17]

Answer : The activation energy for the reaction is, 119.7 J

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at 271 K

$K_2$ = rate constant at 281 K = $2K_1$

$Ea$ = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 271 K

$T_2$ = final temperature = 281 K

Now put all the given values in this formula, we get:

$\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{271K}-\frac{1}{281K}]$

$Ea=119.7J$

Therefore, the activation energy for the reaction is, 119.7 J

3 0

4 years ago