Answer:
4.07
Explanation:
There is some info missing. I think this is the original question.
<em>A solution is prepared at 25 °C that is initially 0.057 M in nitrous acid (HNO₂), a weak acid with Ka = 4.5 × 10⁻⁴, and 0.30 M in sodium nitrite (NaNO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
<em />
Nitrous acid is a weak acid and nitrite (coming from sodium nitrite) is its conjugate base. Together, the form a buffer system. We can calculate its pH using the Henderson-Hasselbach equation.
pH = pKa + log [base]/[acid]
pH = -log 4.5 × 10⁻⁴ + log 0.30/0.057
pH = 4.07
Answer:5
Explann:
I've actually not learnt it but i can solve other questions under Maths
Answer:
Explanation:
<h2>Electromagnetic waves differ from <em>mechanical waves </em>in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.</h2>
Use ideal gas equation: pV = nRT
Now pass n to mass: n = mass / MM .... [MM is the molar mass]
pV = [mass/MM]*RT =>mass/V = [p*MM] / RT and mass / V = density
p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol = 32000 kg/mol
density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L ≈ 1.8 g/L
Then, I do not get any of the option choices.
Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L
Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.
Answer:
- <u><em>50% of the offspring will have green pods.</em></u>
Explanation:
Use a upper case to identify the dominant allele and lower case to identify recessive allele.
<em>A homozygous pea plant</em> would be YY or gg. The <em>homozygous recessive pea pleant</em> would be gg (YY is dominant).
<em>A heterozygous pea plant</em> would be Yg (or gY which is the same).
The <em>Punnett Square </em>for the cross between a <em>homozygous recessive pea plant</em> (gg) and a <em>heterozygous pea plant</em> (Yg) would be:
g g
Y Yg Yg
g gg gg
Hence, <em>the offspring will have</em> two Yg, which would be yellow pods, and two gg which would be green pods.
That is, 50% of the offspring will have yellow pods and 50% will have green pods.
