Answer : The enthalpy change of dissolution of is -54.0 kJ/mole
Explanation :
where,
q = heat released by the solution
c = specific heat of water =
m = mass of solution = mass of water + mass of = 102.00 + 1.69 = 103.69 g
= change in temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change of dissolution of
where,
= enthalpy change of dissolution = ?
q = heat released = 0.659 kJ
m = mass of = 1.69 g
Molar mass of = 138.55 g/mol
Therefore, the enthalpy change of dissolution of is -54.0 kJ/mole
Answer:
The volume increases because the temperature increases and is 2.98L
Explanation:
Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:
V₁/T₁ = V₂/T₂
<em>Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.</em>
In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).
Replacing in the Charles's law equation:
2.36L / 326.15K= V₂/412.15K
<h3>2.98L = V₂</h3>
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Hello!
This may not be accurate, as I am not highly proficient in chemistry, but perhaps inter-molecular bonds is the answer?
Have a wonderful day! :)
-L
Answer:
A chemical equation is the symbolic representation of a chemical reaction.
Explanation: