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Annette [7]
3 years ago
11

In a solution, litmus is blue. The pH of the solution could be 1. 10 2. 2 3. 3 4. 4

Chemistry
1 answer:
yan [13]3 years ago
7 0

Answer:

1. 10

Explanation

when litmus paper is blue that means the solution is basic and 10 on the pH scale is the most basic out of all your options

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If you had an object with a mass of 76g and a volume of 22 ml, what is its density? If you cut this object in half, what would b
V125BC [204]
D = M/V = 76g / 22ml = 3.4g/ml

Half ~ D = 38g / 11ml = 3.4g/ml

Even if the object you had was cut in half, it’s density would remain the same.
8 0
3 years ago
A plant fertilizer contains 15% by mass nitrogen (N). In a container of soluble plant food, there are 14.1 oz of fertilizer. How
masya89 [10]
We are given with the total mass of fertilizer which is 14.1 oz. This is equivalent to 399.73 grams. 15% of the total is the amount of nitrogen. Thus, the nitrogen amount is 59.96 grams.
5 0
3 years ago
How many branches of chemistry are there .​
faltersainse [42]

Answer:

5

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0
3 years ago
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Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

(D) MgSO_4

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}

So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

7 0
3 years ago
CH4 (g) yields C(g) + 4H (g) (reaction for expansion)
anyanavicka [17]

Answer:

Here's what I find.

Explanation:

\rm CH$_{4}$(g) $\, \rightleftharpoons \,$ C(g) + 4H(g)

\text{Same} =\begin{cases}1. & \text{The number of atoms of each element}\\2. & \text{The state of the methane molecules}\\4. &\text{The state of the carbon atoms}\\\end{cases}

\text{Different} =\begin{cases}3. & \text{The enthalpy change of the reaction}\\\end{cases}

The sign of ΔH changes when you reverse the reaction.  

5 0
3 years ago
Read 2 more answers
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