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Annette [7]
3 years ago
11

In a solution, litmus is blue. The pH of the solution could be 1. 10 2. 2 3. 3 4. 4

Chemistry
1 answer:
yan [13]3 years ago
7 0

Answer:

1. 10

Explanation

when litmus paper is blue that means the solution is basic and 10 on the pH scale is the most basic out of all your options

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Calculate the number of O atoms in 0.364 g of CaSO4 · 2H2O
Nikolay [14]

Answer:

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

Explanation:

For problems like this posting, one needs an understanding of the following topics:

The definition of the mole

<u>1 mole of substance</u> = mass in grams of substance containing 1 Avogadro's Number ( = 6.023 x 10²³ ) of particles of the specified substance. This is generally one formula weight of the substance of interest. From this, the following equivalent relationships should be memorized:

<em>   1 mole = 1 formula weight = 1 mole weight (g)= 6.023 x 10²³ particles</em>

Converting grams to moles:

<em>Given grams => moles = grams/gram formula wt </em>

Converting moles to grams:

<em>Given moles => grams = moles x gram formula wt</em>

_________________________________________________________

<em>Calculate the number of O atoms in 0.364 g of CaSO₄ · 2H₂O.</em>

Given mass CaSO₄ · 2H₂O = 0.364 grams

Formula Wt CaSO₄ · 2H₂O = 172 g/mole

moles CaSO₄ · 2H₂O = mass <em>CaSO4 · 2H2O / formula Wt. CaSO₄ · 2H₂O</em>

<em>= 0.364 g CaSO₄·2H₂O </em><em>/ </em><em>172 g CaSO4·2H2O </em>

<em>= (0.364/172) mole CaSO₄·2H₂O </em>

<em>= 2.12 x 10⁻³ mole CaSO₄·2H₂O    </em>

<em>∴ number of Oxy (O) atoms in 0.364 grams CaSO₄·2H₂O </em>

<em>=  (2.12 x 10⁻³ mole CaSO₄ · 2H₂O)(6.023 x 10²³ molecules CaSO₄· 2H₂O/ mole)</em>

<em>= 1.276876 x 10²¹molecules CaSO₄· 2H₂O  CaSO₄2H₂O </em>

<em>= 1.276876 x 10²¹ molecules CaSO₄· 2H₂O   x   6 oxygen atoms / molecule</em>

<em>= 7.661256 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

<em />

8 0
2 years ago
Please someone can help with this answer?
Annette [7]

Answer:

6,000kg/m3

Explanation:

6.00g/1cm3 x 1kg/1000g x 1cm3/0.000001m3

= 6.00kg/0.001m3

= 6,000kg/m3

5 0
3 years ago
What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form
AnnyKZ [126]
<h3>Answer</h3>

HF

<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of \text{F}^{-} ions. The objective is to thus find its conjugate acid or base.

\text{F}^{-} contains no proton \text{H}^{+} and is unlikely to be a conjugate acid. Assuming that \text{F}^{-} is a conjugate base. Adding one proton to \text{F}^{-} would produce its conjugate acid.

\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)

Therefore \text{HF} is the conjugate acid of \text{F}^{-}. \text{HF} happens to be a weak acid. As a result, combining \text{F}^{-} with \text{HF} would produce a solution with large number of both the weak acid and its conjugate base, which is a buffer solution by definition.

4 0
3 years ago
What is the formula unit for a compound made from Pb4+ and oxygen? (3 points)
zavuch27 [327]

The formula unit of compound made up from Pb4+ and oxygen is PbO2.

6 0
3 years ago
Elements are arranged in groups by similar atomic structure on the periodic table. This allows for an element's properties to be
lozanna [386]
A attract a core pair of electrons toward itself
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3 years ago
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