Answer:
C = 39%
H = 5.43%
Explanation:
Firstly, we calculate the number of moles of each.
For carbon, we use carbon iv oxide
Mass here = 0.636g
Number of moles of carbon iv oxide = mass of carbon iv oxide ÷ molar mass of carbon iv oxide. Molar mass = 44g/mol
Number of moles = 0.636 ÷ 44 = 0.014mole
Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.
Mass of carbon = 0.014 × 12 = 0.173g, where 12 is the a.m.u of carbon.
For hydrogen, we use water .
Mass of water = 0.220g
No of moles of water = 0.22 ÷ 18 = 0.012 mole
1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole
Mass of hydrogen produced = 0.024 × 1 = 0.024g
The percentage composition are as follows:
Carbon = 0.173/0.442 × 100 = 39%
Hydrogen = 0.024/0.442 × 100 = 5.43%
