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3 years ago

What is the best definition of "thinking at the margin"? *

Chemistry

1 answer:

Cloud [144]3 years ago

5 0

Answer:

thinking about how to get the most out of a resource

you see thinking at the margin here means, to be thinking to do something out of what you are provided, i.e. to get most out of a resource

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WHO KNOWS HOW TO DO THISSS NEED HELP RN PLS Li PO4 + AlF →

Alecsey [184]

Explanation:

Your chemical equation should look like this:

Li3PO4 + AlF3 --> 3LiF + AlPO4

This is the balanced equation for a double-displacement reaction

4 0

3 years ago

A chemical test has determined the concentration of a solution of an unknown substance to be 2.41 M. a 100.0 mL volume of the so

Oksana_A [137]

Answer : The molar mass of unknown substance is, 39.7 g/mol

Explanation : Given,

Mass of unknown substance = 9.56 g

Volume of solution = 100.0 mL

Molarity = 2.41 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$2.41M=\frac{9.56g\times 1000}{\text{Molar mass of unknown substance}\times 100.0mL}$

$\text{Molar mass of unknown substance}=39.7g/mol$

Therefore, the molar mass of unknown substance is, 39.7 g/mol

5 0

3 years ago

What is the representative unit in a molecular compound

Anastasy [175]

Answer:

A.) A molecule

Explanation:

3 0

3 years ago

Read 2 more answers

In a physical change, the makeup of matter is changed. True or false?

Simora [160]

Answer:

false

Explanation:

because it's just a physical change, the matter won't be changed.

Hope this might help you! I don't know if this is going to be right on everything, but it's a anwser

6 0

3 years ago

A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life

mixas84 [53]

T is amount after time t
Ao is initial amount 
t is time 
HL is half life 

log (At) = log [ Ao x (1/2)^(t/HL) ] 
log (At) = log Ao + log (1/2)^(t/HL) 
log (At) = log Ao + (t/HL) x log (1/2) 

( log At - log Ao) / log (1/2) = t / HL 
log (At/Ao) / log (1/2) = t / HL 

HL = t / [( log (At / Ao)) / log (1/2) ] 

HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] 

HL = 14.4 s / 2 = 7.2 seconds

8 0

3 years ago