Answer:
Option D. 5.5
Explanation:
The equation is this:
2A + 6B ⇒ 3C
With the amounts that we were given, let's determine which is the <em>limting reactant</em>
2 A reacts with 6 B
4 A will react with ( 4 .6)/2 = 12B
I have 11 B, so the limiting is B
6 B react with 2 A
11 B will react with (11 .2 )/6 =3.66 A
I have 4 A, so A is the excess.
6 B produce 3 C
11 B will produce ( 11 .3)/6 = 5.5C
Answer:
A
Explanation:
A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity(Wikipedia).
The formal charge on an atom in a molecule reflects the electron count associated with the atom compared to the isolated neutral atom(University of Calgary).
Looking at all the structures listed A-E for SeO2F2, only structure A minimizes the formal charges for each atom in SeO2F2.
M P₂O₅ = 31g×2 + 16g×5 = 142g/mol
1 mole of P₂O₅ contains 5 moles of atoms
5 moles of atoms = 30,01×10²³ a.
142g ----------- 30,01×10²³ a.
0,69g ---------- X
X = (0,69×30,01×10²³)/142
X = 0,14626×10²³ = 1,4626×10²² atoms
:)
We have to know which two substances are related correctly.
The correct answer is: (C) H₃O⁺ is the conjugate acid of H₂O.
In an acid-base reaction, an acid reacts with a base and gives a conjugate base and conjugate acid. The reaction is shown below:
Acid₁ + Base₂ ⇄ Conjugate Base₁ + Conjugate Acid₂
In the reaction H₂CO₃ + H₂O ⇌ H₃O⁺ + HCO₃⁻, H₂CO₃ is an acid because it releases H⁺ ion and converts to HCO₃⁻. Here HCO₃⁻ is the conjugate base of H₂CO₃ ( according Arrhenius theory).
H₂O accepts H⁺ ion and is converted to H₃O⁺ , thus H₂O behaves as Bronsted base. So, H₃O⁺ is the conjugate acid of Bronsted base H₂O.
Hence, the correct answer is: (C) H₃O⁺ is the conjugate acid of H₂O.
Bleach would increase the pH because Bleach is a basic substance with a pH of about 12
Soda would lower the pH because the pH of sodas is somewhere around 2.5 (this is for coke, other sodas are a bit different)
