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3 years ago

Horatio used the flat end of a hammer to remove a nail from a piece of wood.

2 answers:

3 0

Horatio used the flat end of a hammer to remove a nail from a piece of wood.This is an example of using a hammer as a lever. The answer is A. lever.

scoundrel [369]3 years ago

3 0

<h2>Answer:</h2>

<u>Removing nail by the flat end of the hammer is an example of </u><u>using hammer as a lever</u>

<h2>Explanation:</h2>

Lever is a type of simple machine and we know that machine is anything that makes the work of a human easier. By using hammer to remove a nail from wood is an example of lever. The input force is applied on the handle of hammer and a result the output force is experienced at the nail. Fulcrum is the area between the wood and the mouth of hammer by which we will remove the nail.

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Which of the following is located in the temperature climate zone?

barxatty [35]

The correct answer is C. Taiga hope it helps ( :

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3 years ago

In which of the following elevator situations would the acceleration be positive. Select TWO answers

kap26 [50]

Both options 5 and 6

Explanation:

Let us consider option 5,

In option 5 body is moving up with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

Let us consider option 6,

In option 6 body is moving down with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

4 0

3 years ago

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

$\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}$

$\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}$

$\frac{3-y}{y}=\sqrt{\frac{7}{2}}$

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0

3 years ago

1. When in the past have you pushed your personal limits? Give at least one

Yuri [45]

Answer:

Umm that's a personal question. All u have to do is say when have u pushed your personal limits....... Ummm one for me is when i had to try out for a select soccer and that is past my comfort zone.

Explanation:

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3 years ago

When the distance between two interacting objects doubles, the gravitational force is

Umnica [9.8K]

The gravitational force will be one quarter.

The gravitational force between two objects is given by the formula

F=GMm/r^2

here, r is the distance between the objects.

Thus the gravitational force is inversely proportional to the square of the distance between the objects, Therefore if the distance between two objects is doubled the force will be one quarter.

5 0

3 years ago