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Nata [24]
3 years ago
13

Which statement about electromagnetic waves is true?

Physics
2 answers:
Alborosie3 years ago
8 0

Answer:

B

Good luck! Have a great day!

nevsk [136]3 years ago
3 0
B explanation: I took the quiz hopes this help
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PLEASE HELP ASAP.
kifflom [539]

Volume of the original block (V) of length (l), width (w) and height (h) is given by the following equation

V = l*b*h

hence volume of original block, V =  (6)(4)(10) = 240 cm^{3}

Now say we cut this block in two equal parts, than the length of new block will    be 6/2 = 3 cm ; where as its width and height will be same as of original block i.e. 4 cm and 10 cm respectively.

So, Volume of half-block is = (3)(4)(10) = 120 cm^{3} ; or we can say that the volume of half-block is half that of orignal block.

4 0
3 years ago
The area around a charged object that can exert a force on other charged objects is an electric ___
Ymorist [56]
Answer is:

Electric field.
8 0
4 years ago
SOMEONE PLEASE HELP!!!! <br> Select the correct answer. Which planet is planet A
AURORKA [14]
Saturn is the answer 

4 0
4 years ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
Andrej [43]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

6 0
3 years ago
Why will humans feel lighter on mars?
kotykmax [81]
Because Mars is further from the sun than Earth is, thus the gravitational pull is not as great on Mars as it is on Earth, making us lighter :)
7 0
4 years ago
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