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3 years ago

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What is most likely the amount of energy available at a trophic level of primary consumers if the amount of energy available to

secondary consumers in that food web is 200 kilocalories?
0 kilocalories
20 kilocalories
200 kilocalories
2,000 kilocalories

1 answer:

docker41 [41]3 years ago

6 0

Answer:

200 kilocalories

Explanation:

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Which of the following is an example of electrical energy being converted to chemical energy?

tekilochka [14]

Answer : The correct option is, (B)

Explanation :

Electrical energy : It is defined as the movement of the electrons thought the wire.

Chemical energy : It is a type of energy which is stored in the bonds of a chemical compounds. During the chemical reaction, chemical energy is released in the form of heat.

Sound energy : It is a type of energy which is produced when an object vibrate.

Mechanical energy : It is a type of energy that can be used to do work.

The option A is incorrect because in this process, electrical energy being converted to the sound energy.

The option B is correct because in this process, electrical energy being converted to chemical energy. An oxidation-reduction reaction occurs in the storage battery.

The option C is incorrect because in this process, mechanical energy being converted to mechanical energy.

Hence, the option (B) A storage battery is charged using an electric current is an example of electrical energy being converted to chemical energy.

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3 years ago

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Why are there variations of traits within a population?

nydimaria [60]

Answer:

The variation and distribution of traits in a population depend on genetic and environmental factors. Genetic variation can result from mutations caused by environmental factors or errors in DNA replication, or from chromosomes swapping sections during meiosis.

Explanation:

Hope this helps!

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3 years ago

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You are driving in a car for 30 minutes, with the windows down and the radio at a high volume. You turn the car off and leave th

matrenka [14]

Answer:

sensory adaption

Explanation:

Sensory adaption is the phenomenon where the intensity of a stimulus experienced by an organism decreases after a certain amount of exposure to the stimulus. This happens in order for us to pay attention to other stimulus.

When you are driving with the windows down and listening to music you are subjected to a lot of stimuli. Here, most of our attention needs to be on driving. So, our brain drowns all the other unneccessary stimuli like the music.

When you enter the car again where the other stimuli which were present while driving are absent, all your attention is diverted to the music. So, your're ears hurt.

6 0

3 years ago

A 0.500-kg potato is fired at an angle of 80.0° above the horizontal from a PVC pipe used as a "potato gun" and reaches a height

lions [1.4K]

Answer:

(a) $47.15ms^{-1}$

(b) $2470.13ms^{-2}$

(c) 1235.06N and 252.05 as a ratio

Explanation:

From Newton's second law of motion

F=ma where m is mass, a is acceleration and F is net force

Also from kinetic equation of motion, velocity and displacement are related using equation

$v^{2}=u^{2}+2sa$

Where v is final velocity, u is initial velocity, a is acceleration and s is displacement

From the free body diagram attached, final velocity at maximum height is 0 and initial velocity is $usin80^{o}$

Also, the vertical component can be written as

$v_{y}^{2} }=u_{y}^{2} } -2gs$ The negative sign before 2gs means displacement is opposite the gravitational force

Where g is acceleration due to gravity, $u_{y}$ is vertical component of initial velocity and $v_{y}$ is vertical component of final velocity

Since $v_{y}$ is 0

$u_{y}^{2} } =2gs$

s=110 and g is taken as 9.8

$u_{y}=\sqrt{2*9.8*110}=46.43275$

$u_{y}=46.43ms^{-1}$

Also, it's evident that the vertical component of initial velocity is $u_{y}=u_{i}sin \theta$ where $\theta$ is angle of projection and $u_{i}$ is resultant velocity

Making $u_{i}$ the subject we obtain $u_{i}=\frac {u_{y}}{sin \theta}$

Since $u_{y}$ and $\theta$ are known as $46.43ms^{-1}$ and $80^{o}$ respectively, then $u_{i}=\frac {46.43ms^{-1}}{sin 80^{o}}=47.15ms^{-1}$

Therefore, the velocity of potato is $47.15ms^{-1}$

(b)

Displacement depends on length of tube hence s=0.450m hence going back to kinetic equation $v^{2}=u^{2}+2sa$

The final velocity v is answer in part a which is $47.15ms^{-1}$ , initial velocity u is $0ms^{-1}$ hence the equation is re-written as

$v^{2}=2sa$ and making a the subject we obtain

$a=\frac {v^{2}}{2s}$

$a=\frac {47.15^{2}}{2*0.450}=2470.13ms^{-2}$

Therefore, average acceleration is $2470.13ms^{-2}$

(c)

From Newton's second law of motion, F=ma where m=0.500kg and a is $2470.13ms^{-2}$

Therefore, the average force of potato is

F=0.5*2470.13=1235.06N

F=1235.06N

The weight, W of potato is given by W=mg

Taking R as ratio of average force and weight of potato

$R=\frac {F}{W}=\frac {F}{mg}$ and since F=1235.06, m=0.500kg and g=9.8

$R=\frac {1235.06}{0.500*9.8}$ =252.05

Therefore, ratio of average force to weight is 252.05

8 0

4 years ago

3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P

KIM [24]

Answer:

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

$E=\frac{F}{Q}$

But the force F

$F= \frac{kQ1Q2}{r^2}$

But the electric field intensity due to a point charge Q at a distance r meters away is given by

$E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }$

<em>From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases</em>

6 0

3 years ago