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AleksAgata [21]
3 years ago
6

A bicyclist on an old bike (combined mass: 92 kg) is rolling down (no pedaling or braking) a hill of height 120 m. Over the cour

se of the 384 meters of downhill road, she encounters a constant friction force of 261 Newton. If her speed at the top of the hill is 9 m/s, what is her speed at the bottom of the hill

Physics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

V2 = 15.9m/s

Explanation:

See attachment below.

Finger [1]3 years ago
3 0

Answer:

V = 48.49m/s

Explanation:

Given the following information:

Combined mass = 92kg

Hill's height = 120m

Course of ride = 384m

Frictional force = 261N

Initial speed (u) = 9m/s

Final speed (v) = ?

Since we are looking for her speed at the bottom,

Time = distance/speed = 384m/9m.s

Time = 42.67s

we use the equation

H = V²/2g ( equation for maximum heigh of trajectory)

Therefore, plugging the values we have

120 = V²/2×9.8

V² = 9.8×120×2

V = √2352

V = 48.49m/s

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an example for power could be a nuclear plant; traditional nuclear plants produce somewhat close to 1 giga watts (which means 1 giga joules in a second)


3 0
2 years ago
3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final
MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m =  9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0
2 years ago
A large asteroid of mass 98700 kg is at rest far away from any planets or stars. A much smaller asteroid, of mass 780 kg, is in
Citrus2011 [14]

Answer:

1.81 x 10^-4 m/s

Explanation:

M = 98700 kg

m = 780 kg

d = 201 m

Let the speed of second asteroid is v.

The gravitational force between the two asteroids is balanced by the centripetal force on the second asteroid.

\frac{GMm}{d^{2}}=\frac{mv^2}{d}

v=\sqrt{\frac{GM}{d}}

Where, G be the universal gravitational constant.

G = 6.67 x 10^-11 Nm^2/kg^2

v=\sqrt{\frac{6.67 \times 10^{-11}\times 98700}{201}}

v = 1.81 x 10^-4 m/s

7 0
3 years ago
Summarize renewable energy saves water and creates jobs
siniylev [52]

Answer: Solar Energy has been helping the supplying companies to be able to hire more people for jobs which helps 12 times more easier than the US,  Things like solar, geothermal, and wind can help reduce the water resources which helps to save our water conservation rate which was getting increasingly High.

<em>I hope this explanation had helped you today!</em>

4 0
2 years ago
How much time would it take for an airplane to reach its destination if it traveled at an average velocity of 820 km/hr NE for a
Vladimir79 [104]

Answer:

Time, t = 6.34 hours.

Explanation:

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{displacement}{time}

Therefore, making time the subject of formula;

Time = \frac{displacement}{velocity}

Given the following data;

Displacement = 5200km

Average velocity = 820km/hr

Substituting into the equation, we have;

Time = \frac{5200}{820}

Time = 6.34 hours.

<em>Hence, it would take 6.34 hours for the airplane to reach its destination. </em>

5 0
3 years ago
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