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Stella [2.4K]
2 years ago
11

alculate the molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution.

Chemistry
1 answer:
valentina_108 [34]2 years ago
5 0

The molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution is 2.3 M.

<h3>What is Molarity? </h3>

Molarity is defined as the ratio of number of moles of solute to the volume of the solution.

Molarity = number of moles of solute/ Volume of solution

Given,

given mass of sodium hydroxide= 20 g

Volume of the solution = 200 mL.

Firstly, we will calculate the moles of sodium hydroxide.

<h3>What is Mole? </h3>

Mole is defined as the ratio of given mass of substance to the molar mass of substance.

Mole = given mass/ molar mass

Molar mass of sodium hydroxide = 40 g

Mole = 20/40

= 0.5 mol

Molarity = (0.5/ 200) × 1000 = 2.5M

Thus, we calculated that the molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution is 2.3 M.

learn more about Molarity:

brainly.com/question/19517011

#SPJ4

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Calculate the standard entropy change for the industrial synthesis of urea (a common fertilizer): CO2(g) + 2 NH3(g) → CO(NH2)2(s
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Answer : The standard entropy change is, -424.1 J/K

Explanation :

The given balanced reaction is,

CO_2(g)+2NH_3(g)\rightarrow CO(NH_2)_2(s)+H_2O(l)

The expression used for entropy change of reaction (\Delta S^o) is:

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{CO(NH_2)_2}\times \Delta S^0_{(CO(NH_2)_2)}+n_{H_2O}\times \Delta S^0_{(H_2O)}]-[n_{CO_2}\times \Delta S^0_{(CO_2)}+n_{NH_3}\times \Delta S^0_{(NH_3)}]

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\Delta S^o = entropy change of reaction = ?

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\Delta S^0_{(CO(NH_2)_2)} = 104.6 J/mol.K

\Delta S^0_{(H_2O)} = 69.91 J/mol.K

\Delta S^0_{(CO_2)} = 213.74 J/mol.K

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Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (104.6J/K.mole)+1mole\times (69.91J/K.mole)}]-[1mole\times (213.74J/K.mole)+2mole\times (192.45J/K.mole)]

\Delta S^o=-424.1J/K

Therefore, the standard entropy change is, -424.1 J/K

3 0
3 years ago
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