Answer:
wo = 18.75 rev / s
Explanation:
This is an exercise in endowment kinematics, it indicates that the final angular velocity is w_f = 109 rad / s, the time to reach this velocity is t = 1.87 s and the deceleration a = 4.7 rad / s²
w_f = w₀ - a t
w₀ = w_f + a t
w₀ = 109 + 4.7 1.87
w₀ = 117.8 rad / s
let's reduce to revolutions / s
w₀ = 117.8 rad / s (1 rev / 2pi rad)
w₀ = 18.75 rev / s
Answer:
THE RUBBER BALL
Explanation:
From the question we are told that
The mass of the rubber ball is 
The initial speed of the rubber ball is 
The final speed at which it bounces bank 
The mass of the clay ball is 
The initial speed of the clay ball is 
The final speed of the clay ball is 
Generally Impulse is mathematically represented as
where
is the change in the linear momentum so

For the rubber is


=> 
For the clay ball


=> 
So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball
The tilt of the moon's axis does not allow for monthly alignment, so the lunar and solar eclipse do not happen every month.
<h3>How do the lunar and solar eclipse occur?</h3>
- For the occurrence of lunar and solar eclipse, the sun, moon and the earth must remain in a plan and along a straight line.
- When the earth appears in between the sun and the moon, lunar eclipse occurs.
- When the moon appears in between the sun and the earth, solar eclipse occurs.
- The moon and earth are rotating not only around the sun, but also around the black hole of Milky way galaxy.
- So they are not present in a plan as well as in a straight line in every full moon and new moon time.
Thus, we can conclude that the option D is correct.
Learn more about the lunar eclipse and solar eclipse here:
brainly.com/question/8643
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Answer:
Explanation:
Given
for 
Sphere are 
when sphere
apart suppose deflection is 
We know

Where F=force between charged particle
Deflection


thus 
for 



(b)for
deflection Potential 
Electric Potential is 

where V=voltage
k=constant
r=distance between charges
Put value of Q in equation 1


thus 
therefore


