Answer:
B im so sorry if its wrong im sure it right
Explanation:
see it has the lowest specific heat so it wouldnt cool because of the bionestint particles
Answer:
41.4 s
Explanation:
Given data
- Rate constant (k): 8.42 × 10⁻² s⁻¹ at 800 °C
- Initial concentration of A ([A]₀): 5.00 M
- Concentration of A at a time t ([A]): 0.153 M
Let's consider the following reaction of first order with respect to A.
2 A ⇒ B
We can find the time that it will take for A to decrease from 5.00 M to 0.153 M using the following expression.
![ln([A]/[A]_0)=-k.t\\ln(0.153M/5.00M)=-8.42 \times 10^{-2}s^{-1} .t\\t = 41.4 s](https://tex.z-dn.net/?f=ln%28%5BA%5D%2F%5BA%5D_0%29%3D-k.t%5C%5Cln%280.153M%2F5.00M%29%3D-8.42%20%5Ctimes%2010%5E%7B-2%7Ds%5E%7B-1%7D%20%20%20.t%5C%5Ct%20%3D%2041.4%20s)
NH₄CN is a salt formed from weak base NH₄OH and weak acid HCN so that it undergoes complete hydrolysis
<h3>Further explanation</h3>
The hydrolysis process is a term used for the reaction of substances with water
There are 3 types of hydrolysis salts
1.Salt from strong acids and strong bases does not undergo hydrolysis so that the pH of the neutral solution = 7
2.Salt from strong acids and weak bases (pH <7) or from strong bases and weak acids (pH> 7) will be partially / partially hydrolyzed
3.Salt from weak acids and weak bases (pH depends on the value of Ka and Kb) will be completely hydrolyzed
NH₄CN is a salt formed from weak base NH₄OH and weak acid HCN so that it undergoes complete hydrolysis
NH₄OH + HCN⇒NH₄CN+H₂O
Can be formulated :
![\tt [H^+]=\sqrt{\dfrac{Kw\times Ka}{Kb} }](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7B%5Cdfrac%7BKw%5Ctimes%20Ka%7D%7BKb%7D%20%7D)
Ka> Kb then [H +]> 7 and pH <7 ⇒ acidic
Ka <Kb then [H +] <7 or pH> 7 ⇒alkaline
Ka = Kb then pH = 7 ⇒neutral
The molar mass or As is 74.9g. Start with 281g multiply by (1mol/74.9g) = 3.75 mols
Put what you don’t want on the bottom (in this case grams) so they the u it’s cancel (if you multiply by grams and the divide by grams they cancel. Ultimately leave what you want on the top ( This case mols) then do the math