All categories

3 years ago

The value of Zeff for a valence electron in an atom of silicon is?

1 answer:

6 0

Zeff is the effective nuclear charge wherein, Z resembles the number of protons in the nucleus while S corresponds to the number of non-valence electrons.

Zeff = Z - S

Silicon has 14 protons; its electron configuration is [Ne] 3s2 3p2. Its non-valence electrons is in the n = 1 and n =2 shells. There are 2 electrons in n = 1 and 8 in n = 2, so there are a total of 10 non-valence electron.

Zeff= 14−10= 4

So, the answer is 4.

You might be interested in

Which of the following represents the least number of molecues?

Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

$molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}$

So, let´s get the number of molecules for each of the options.

$a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules$

$b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules$

$c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules$

$d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules$

$d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules$

the smalest number is in option a)

Best of luck.

7 0

2 years ago

I WILL MARK BRAINLIEST PLZ HELP ASAP, thanks :)

7nadin3 [17]

Answer:

Inner

Explanation:

3 0

3 years ago

Sixty-five percent of the mass of bone is a compound called hydroxyapatite. sixty-five percent of the mass of bone is a compound

mafiozo [28]

True. Its simple how i remeberd was the bone has 650,000 cells and the bone has 65% hydroxyapatite

5 0

2 years ago

In what type of radioactive decay does the atomic number of the product decrease by one? Select all that apply.

VladimirAG [237]

The atomic number of the product decrease by one in the d) positron emission and the e) electron capture radioactive decay. These radioactive decays are two of three common forms of the Beta Decay which occurred when the proton released a positron and a neutron emitted an electron. The Beta Decay can increase or decrease the atomic number.

4 0

2 years ago

Help ;-; Will give Brainliest and 25 Points

Yuri [45]

I don’t see what you need help with but thanks:)

3 0

2 years ago

Read 2 more answers