Substances that posses an excess it greater amount of hydroxide ions are considered basic, or alkali like in solution. They would thus showcase properties of a basic substance.
9.01 × 10⁻²⁶ J
<h3>Explanation</h3>
ΔE = h · f
Where
- ΔE the change in energy,
- h the planck's constant, and
- f frequency of the emission.
However, only λ is given.
f = c / λ
Where
- f frequency of the emission,
- λ wavelength of the emission, and
- c the speed of light.
For this emission:
f = 2.998 × 10⁸ / 2.21 = 1.36 × 10⁸ s⁻¹.
ΔE = h · f = 6.626 × 10⁻³⁴ × 1.36 × 10⁸ = 9.01 × 10⁻²⁶ J
For this item, we find first the mass of the compound with the empirical formula. That is,
molar mass = 12 (for C) + 1 (for H)
= 13 g/mole
Then, we divide the given mass of the molecular formula by the mass of the empirical formula.
n = 52.07 / 13 = 4
Therefore, the molecular formula is C₄H₄.
The correct response is A. Non-disjunction of sex chromosomes.
