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Sav [38]
3 years ago
6

Solve for x: -2x - 4 > 8

Mathematics
1 answer:
allochka39001 [22]3 years ago
3 0
The answer is in the photo above

You might be interested in
1. 5X - 3 = 2x + 12 <br> 2. 3 (X - 5) = 2 (X - 1)<br> 3. 5x - 6 + 2 (X + 2) = 3x + 7
victus00 [196]
1. x = 5
2. x = -17
3. x = 2.25
Hope this helped!
4 0
3 years ago
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
alexandr402 [8]

Answer:

1) H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

2) The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married             21                         37                               58                  116

Not Married      59                        63                               42                  164

Total                  80                        100                             100                 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married         33.143                    41.429                        41.429              116

Not Married  46.857                   58.571                        58.571              164

Total                  80                        100                             100                 280

Part 3

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(2-1)(3-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

8 0
2 years ago
9.9 ft<br> 7.2 ft<br> What is the length ? I’m
GarryVolchara [31]

Answer:

minus

the question is not complete

3 0
2 years ago
Consider the function f(x)= 1-|x-1|+|x+1| for -3&lt;x&lt;3. Recall that the absolute function can be represented as a piece wise
Kruka [31]
By the definition for the absolute value,

|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x
|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x

So for the compound function f(x)=1-|x-1|+|x+1|, there are three intervals to consider. What happens when x? when -1\le x? when x\ge1?

You have

f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x
8 0
3 years ago
Y= 1/2x -3 on a graph<br> I’m confused on how to graph 1/2x - 3
amid [387]

Answer:

Put your equation into this!

Step-by-step explanation:

desmos.com/calculator

It will graph it for you!

You are very welcome!!

3 0
3 years ago
Read 2 more answers
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