A gas at 42. 0°c occupies a volume of 1. 32 l. if the volume increases to 2. 24 l, what is the new temperature in kelvin?

Why is a shoe considered individual evidence

vlada-n [284]

Because someone was wearing it and their dna could be in it i’m guessing

6 0

3 years ago

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denis23 [38]

Using the gas laws, the volume of nitrogen produced is 6.6 L.

<h3>What is the product of a reaction?</h3>

We know that the product of a reaction is obtained from the balanced reaction equation. The reactants combine together to yield the products hence we have; N2 + 3H2 ----> 2NH3

We know that 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 25500 L

x = 1 mole * 25500 L/ 22.4 L

x = 1138.4 moles

If 3 mole of hydrogen reacts with 1 mole of nitrogen

1138.4 moles reacts with 1138.4 moles * 1 mole/ 3 moles = 379.5 moles

Mass of nitrogen = 379.5 moles * 28 g/mol = 10626 g

Now 3 moles of hydrogen produces 44.8 L of NH3

1138.4 moles produces 1138.4 moles * 44.8 L/ 3 moles = 17000 L

Now;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 17000 * 848/5.5 * 273

V2 =9601 L

2) 2NH4NNO3(s) ---> 4H2O(g) + 2N2(g) + O2(g)

Number of moles = 12g/ 80 g/mol = 0.15 moles

Now;

2 moles of NH4NNO3 produced 2 moles of nitrogen hence 0.15 moles of N2 was produced.

1 mole of N2 occupies 22.4 L

0.15 moles of N2 occupies 0.15 moles * 22.4 L/1 mole = 3.36 L

P1 = 760 torr

V1 = 3.36 L

T1 = 273 K

P2 = 745 torr

T2 = 527 degrees or 800 K

V2 = ?

V2 = P1V1T2/P2T1

V2 = 760 * 3.36 * 527/745 * 273

V2 = 6.6 L

Learn more about gas laws:brainly.com/question/12669509

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3 0

2 years ago

What is the molarity of a solution made by mixing 50.0 g of magnesium nitrate, Mg(NO3)2, in enough water to make 250. mL of solu

Ira Lisetskai [31]

............................

8 0

4 years ago

HELP IM AB TO CRY

Lemur [1.5K]

Answer:

1.23 × 10³ N

Explanation:

Step 1: Given and required data

Mass of the person (m): 125 kg

Acceleration due to the gravitational force (g): 9.81 m/s²

Step 2: Calculate the force acting between the Earth and a 125-kg person standing on the surface of the Earth

We will use Newton's second law of motion.

F = m × g

F = 125 kg × 9.81 m/s²

F = 1.23 × 10³ N

8 0

3 years ago

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti

ss7ja [257]

Answer:

1.89 of Sodium Carbonate

3.94 g of Silver Carbonate

2.43 g of Sodium Nitrate

Zero grams of Silver Nitrate

Explanation:

We have to start with the reaction:

$AgNO_3~+~Na_2CO_3~->~Ag_2CO_3~+~NaNO_3$

Now, we can balance the reaction:

$2AgNO_3~+~Na_2CO_3~->~Ag_2CO_3~+~2NaNO_3$

Now, we have to calculate the limiting reagent and we have to follow a few steps:

1) Convert to moles (using the molar mass of each compound)

2) Divide by the coefficient of each reactive (given by the balanced reaction)

Convert to moles

$3.40~g~Na_2CO_3\frac{105.98~g~Na_2CO_3}{1~mol~Na_2CO_3}=0.032~mol~Na_2CO_3$

$4.86~g~AgNO_3\frac{169.8~g~AgNO_3}{1~mol~AgNO_3}=0.0286~mol~AgNO_3$

Divide by the coefficient

$\frac{0.032~mol~Na_2CO_3}{1}=0.032$

$\frac{0.0286~mol~AgNO_3}{2}=0.0143$

The smallest value is for $AgNO_3$ , therefore the 4.86 g of $AgNO_3$ .

Now we can calculate the amount of compounds produced is we follow a few steps:

1) Use the molar ratio

2) Convert to moles (using the molar mass of each compound)

Amount of Silver Carbonate

$0.0286~mol~AgNO_3\frac{1~mol~AgCO_3}{2~mol~AgNO_3}\frac{275.74~g~AgCO_3}{1~mol~AgCO_3}=3.94~g~AgCO_3$

Amount of Sodium Nitrate

$0.0286~mol~AgNO_3\frac{2~mol~NaNO_3}{2~mol~AgNO_3}\frac{84.99~g~NaNO_3}{1~mol~NaNO_3}=2.43~g~NaNO_3$

Amount of Sodium Carbonate (Excess reactive)

$0.0286~mol~AgNO_3\frac{1~mol~NaCO_3}{2~mol~AgNO_3}\frac{105.98~g~NaCO_3}{1~mol~NaCO_3}=1.51~g~NaCO_3$

$3.4~g~NaCO_3-1.51~g~NaCO_3=1.89~g~NaCO_3$

Amount of Silver Nitrate

All the silver nitrate would be consumed in the reaction

I hope it helps!

7 0

4 years ago