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Elena-2011 [213]
3 years ago
13

What is a hot spot? Must be in your own words ( please hurry)

Chemistry
2 answers:
kenny6666 [7]3 years ago
7 0

Answer:

It depends. what hot spot are you looking for?

vodka [1.7K]3 years ago
4 0

Answer:

A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.

Explanation:

Hope this is what you mean be hot spot!

I hope this helps you!  

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Why do chemical equations need to be balanced?
velikii [3]
Because if they are not balanced, then the amount of reaction is not equal to the amount of the product. You must have the same ratio of atoms on both sides of the equation because we are not losing moles of each element.
7 0
3 years ago
Calculate the number of moles present in 9.50g of co2
pshichka [43]

Answer:

0.4318 mol

Explanation:

Moles= mass/ mollar mass

Moles= 9.50/22

Moles= 0.4318 mol

3 0
3 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
2 years ago
The table shows data for two groups of plants one grown with fertilizer and the other without fetalizer was the mean height of t
AleksAgata [21]

Answer:

What is the question?

Explanation:

6 0
2 years ago
Read 2 more answers
Can anyone do this question.i really need a answer​
PilotLPTM [1.2K]

Answer:

17.4

Explanation:

kasi 15.2

16.2

=17.4 thanks me later pa brainliest din

7 0
3 years ago
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