We don't know Carter, and we don't know where he is or what 
he's doing, so I'm taking a big chance speculating on an answer.
I'm going to say that if Carter is pretty much just standing there, 
or, let's say, lying on the ground taking a nap, then the force of 
the ground acting on him is precisely exactly equal to his weight.
        
             
        
        
        
Given:
u(initial velocity)=0
a=5.54m/s^2
v(final velocity)=2 m/s
v=u +at
Where v is the final velocity.
u is the initial velocity
a is the acceleration.
t is the time
2=0+5.54t
t=2/5.54
t=0.36 sec
 
        
             
        
        
        
Answer:
The atmospheric pressure is  .
.
Explanation:
Given that,
Atmospheric pressure  
     
drop height h'= 27.1 mm
Density of mercury 
We need to calculate the height
Using formula of pressure

Put the value into the formula



We need to calculate the new height




We need to calculate the atmospheric pressure
Using formula of atmospheric pressure

Put the value into the formula


Hence, The atmospheric pressure is  .
.
 
        
             
        
        
        
B student 2 because you add
        
             
        
        
        
It is D as it is the only answer referring to weather and climate.