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Talja [164]
3 years ago
9

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillation are

completed and 35.5 seconds, the acceleration is
a) 7.52 m/s squared

b) 9.81 m/s squared

c) 30.5 m/s squared

d) 42.0 m/s squared
Physics
1 answer:
givi [52]3 years ago
6 0

Answer :

Explanation :

It is given that,

length of pendulum, l = 0.6 m

Number of oscillation, n = 20

time, t = 35.5 seconds

so, Time period, T=\dfrac{t}{n}

T=\dfrac{35.5s}{20}

we know that the time period of pendulum is given by

T=2\pi\sqrt{\dfrac{l}{g}}

g=\dfrac{4\pi^2l}{T^2}

g=\dfrac{4\times(3.14)^2\times 0.6 \times (20)^2}{(35.5s)^2}

g=7.51\ m/s^2

or

g=7.52\ m/s^2

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