The total work done is 5980 Joules and the power expended is 57 Watts.
<h3>What is work done?</h3>
The work done is the work done in the gravitational field as the bucket is raised up Thus work required to remove the bucket Wb;
Wb = 13.9 kg * 25.9 m * 9.8 m/s^2 = 3530 Joules
Height of the center of mass of chain = 25.9 / 2 = 12.95 m
Work done by the chain Wc;
Wc = 12.95 * 19.3 * 9.8 = 2450 Joules
Total work = 3530 + 2450 = 5980 Joules
Power expended = W / t = 5980 J / 105 sec = 57 J/s = 57 Watts
Learn more about work done:brainly.com/question/13662169
#SPJ1
The answer would be 27,000 Joules because (1/2) m v^2 =30*900 which equals 27,000 J
Answer:
500km
Explanation:
Given parameters:
Speed = 200km/hr
Time taken = 2.5hrs
Unknown:
Distance = ?
Solution:
To solve this problem, we use the speed, time and distance equation.
Therefore;
Distance = Speed x time
So;
Distance = 200 x 2.5 = 500km
Answer:
correct option is a. True
Explanation:
solution
the noise floor is AWGN ( additive white Gaussian noise )
and when viewed in the frequency domain, it is the continuous noise level
because as they have a uniform power over all the frequency.
so that it is additive white Gaussian noise
as we can say given statement is True
correct option a true
<u>Answers</u>
(a) 6.75 Joules.
(b) 5.27 m/s
(c) 0.75 Joules
<u>Explanation</u>
Kinetic energy is the energy possessed by a body in motion.
(a) its kinetic energy at A?
K.E = 1/2 mv²
= 1/2 × 0.54 × 5²
= 6.75 Joules.
(b) its speed at point B?
K.E = 1/2 mv²
7.5 = 1/2 × 0.54 × V²
V² = 7.5 ÷ 0.27
= 27.77778
V = √27.77778
= 5.27 m/s
(c) the total work done on the particle as it moves from A to B?
Work done = 7.5 - 6.75
= 0.75 Joules