Answer:
the sheets approach while the object is near
Explanation:
An electroscope is an apparatus that has two metal sheets attached, when these sheets have a charge and distribute evenly between them and the sheets repel.
When I approach an object charged with a counter (negative) charge, part of the charge of the electroscope moves near the charged external object, to neutralize the electric field, so as the charge on one of the plates decreases the electroscope has approached , as the objects are not touched the system remains in this configuration while the object is close. When the object is released, the electric field it creates disappears, so the positive charges repel inside the electroscope and the sheets repel to the initial position.
In short, the sheets approach while the object is near
Answer:
6 x 10⁻¹⁵ J
Explanation:
d = distance between the plates = 1.5 cm = 0.015 m
E = magnitude of electric field between the plates of the capacitor = 2.5 x 10⁶ V/m
q = magnitude of charge on the electron = 1.6 x 10⁻¹⁹ C
Force on the electron due to electric field is given as
F = q E
F = (1.6 x 10⁻¹⁹) (2.5 x 10⁶)
F = 4 x 10⁻¹³ N
KE₀ = initial kinetic energy of electron at negative plate = 0 J
KE = final kinetic energy of electron at positive plate = ?
Using work-change in kinetic energy
F d = KE - KE₀
(4 x 10⁻¹³) (0.015) = KE - 0
KE = 6 x 10⁻¹⁵ J
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