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4vir4ik [10]
2 years ago
13

Methane (CH4), is said to be the cleanest burning fossil fuel. When burned, it releases carbon dioxide gas and forms water. Usin

g the equation below, determine which of the following is true (assuming there is an infinite supply of oxygen gas (O2)). Select all that apply.
For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.


For every 2 moles of methane (CH4) that reacts, 2 moles of H2O are produced.


For every 2,000 molecules of methane (CH4) that reacts, 2,000 molecules of H2O are produced.


For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.


For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
Chemistry
1 answer:
LiRa [457]2 years ago
3 0

From the stoichiometry of the balanced reaction equation, the correct statement are;

  • For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
  • For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
  • For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.

<h3>What is combustion?</h3>

The term combustion refers to the burning of fossil fuels for the purpose of energy production. The equation for reaction is CH4 + 2O2 ---> CO2 + 2H2O.

Using this equation as shown, the true statements are;

  • For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
  • For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
  • For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.

Learn more about combustion: brainly.com/question/15117038

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According to the law of constant composition, how many grams of oxygen does this isolated sample contain?
KatRina [158]

The Mass of oxygen in isolated sample is 8.6 g

<h3>What is the Law of Constant composition?</h3>

The law of constant composition states that pure samples of the same compound contain the same element in the same ratio by mass irrespective of the source from which the compound is obtained.

Considering the given ascorbic acid samples:

Laboratory sample contains 1.50 gg of carbon and 2.00 gg of oxygen

mass ratio of oxygen to carbon is 2 : 1.5

Isolated sample will contain 2/1.5 * 6.45 g of oxygen.

Mass of oxygen in isolated sample = 8.6 g

In conclusion, the mass of oxygen is determined from the mass ratio of oxygen and carbon in the compound.

Learn more about the Law of Constant composition at: brainly.com/question/1557481

#SPJ1

Note that the complete question is given below:

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Another sample of ascorbic acid isolated from citrus fruits contains 6.45 gg of carbon. According to the law of constant composition, how many grams of oxygen does this isolated sample contain?

Express the answer in grams to three significant figures.

8.47 g

8 0
1 year ago
Which example is NOT a model?
lidiya [134]

Answer:

B

Explanation:

i think leter B it because

7 0
3 years ago
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slamgirl [31]

Answer:

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4 0
2 years ago
Why does hydrogen fluoride have a high boiling point
mezya [45]

The intermolecular bonding for HF is van der Waals, whereas for HCL, the intermolecular bonding is hydrogen. Since the van der Waals bond is stronger than hydrogen, HF will have a higher boiling temperature. Since the covalent bond is stronger than van der Waals, HF will have a higher boiling temperature.

3 0
2 years ago
what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a
WARRIOR [948]

Answer : The  

pH of a solution is, 8.56

Explanation : Given,

K_b=1.8\times 10^{-5}

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of pK_b.

The expression used for the calculation of pK_b is,

pK_b=-\log (K_b)

Now put the value of K_b in this expression, we get:

pK_b=-\log (1.8\times 10^{-5})

pK_b=5-\log (1.8)

pK_b=4.7

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

pOH=pK_b+\log \frac{[Salt]}{[Base]}

Now put all the given values in this expression, we get:

pOH=4.7+\log (\frac{0.55}{0.10})

pOH=5.44

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56

Thus, the pH of a solution is, 8.56

8 0
2 years ago
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