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Gnesinka [82]
3 years ago
9

Match each term to the best description. ::

Physics
1 answer:
dusya [7]3 years ago
6 0
These are the matched answers:

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Farmer Brown has sprayed his fields to kill the grasshoppers eating the grass in his pastures. Predict what will happen to the o
Helga [31]
Its a major factor in the food chain the grass hopers could be gone and some other animals and insects would die from starving and it would mess up the entire food chain for that area hope this helps had the same free response for k12 plz give me brainliest thx
3 0
3 years ago
After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T
oksian1 [2.3K]

Answer:

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity I = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

at what distance from the explosion is the sound intensity half this value?

we know that;

Sound intensity I is proportional to 1/(distance)²

i.e

I ∝ 1/r²

Now, let r² be the distance where sound intensity is half, i.e I₂ = I₁/2

Hence,

I₂/I₁ = r₁²/r₂²

1/2 = (165)²/ r₂²

r₂² = 2 × (165)²

r₂² = 2 × 27225

r₂² = 54450

r₂ = √54450

r₂ = 233.35 m

Therefore, required distance is 233.35 m

6 0
3 years ago
A commuter train passes a passenger platform at a constant speed of 40.4 m/s. The train horn is sounded at its characteristic fr
mihalych1998 [28]

(a) -83.6 Hz

Due to the Doppler effect, the frequency of the sound of the train horn appears shifted to the observer at rest, according to the formula:

f' = (\frac{v}{v\pm v_s})f

where

f' is the apparent frequency

v = 343 m/s is the speed of sound

v_s is the velocity of the source of the sound (positive if the source is moving away from the observer, negative if it is moving towards the observer)

f is the original frequency of the sound

Here we have

f = 350 Hz

When the train is approaching, we have

v_s = -40.4 m/s

So the frequency heard by the observer on the platform is

f' = (\frac{343 m/s}{343 m/s - 40.4 m/s})(350 Hz)=396.7 Hz

When the train has passed the platform, we have

v_s = +40.4 m/s

So the frequency heard by the observer on the platform is

f' = (\frac{343 m/s}{343 m/s + 40.4 m/s})(350 Hz)=313.1 Hz

Therefore the overall shift in frequency is

\Delta f = 313.1 Hz - 396.7 Hz = -83.6 Hz

And the negative sign means the frequency has decreased.

(b) 0.865 m

The wavelength and the frequency of a wave are related by the equation

v=\lambda f

where

v is the speed of the wave

\lambda is the wavelength

f is the frequency

When the train is approaching the platform, we have

v = 343 m/s (speed of sound)

f = f' = 396.7 Hz (apparent frequency)

Therefore the wavelength detected by a person on the platform is

\lambda' = \frac{v}{f'}=\frac{343 m/s}{396.7 Hz}=0.865m

5 0
3 years ago
b. Comparing and Contrasting Compare the change in atmospheric pressure with elevation to the change in water pressure
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Answer:

hfyn done hm jjhohhy u kk

3 0
3 years ago
Read 2 more answers
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marusya05 [52]

Answer:

it is 2236392000

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2 years ago
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