Answer
Correct Answer is B,D, F and G
Explanation:
If a kid has any type of delays in his physical or mental growth then he need intervention service.
For example if a kid is not able to walk after 18 month, if a kid is not able to speak properly after 3 years, if a kid of 5 years age has lack of response to typical efforts to engage him in an interaction then these kids need intervention service.
Answer:
Essentially, your thumb is the main piece of your body that has saddle joints. The bones in your seats joint are in charge of moving forward and backward, side to side.
When all is said in done, the piece of the thumb joint that is subjected to extreme anxiety is that known as CMC joint or carpometacarpal joint. This joint is fundamentally shaped by the metacarpal bone and it explains with the trapezium bone of the wrist.
Explanation:
-- The string is 1 m long. That's the radius of the circle that the mass is
traveling in. The circumference of the circle is (π) x (2R) = 2π meters .
-- The speed of the mass is (2π meters) / (0.25 sec) = 8π m/s .
-- Centripetal acceleration is V²/R = (8π m/s)² / (1 m) = 64π^2 m/s²
-- Force = (mass) x (acceleration) = (1kg) x (64π^2 m/s²) =
64π^2 kg-m/s² = 64π^2 N = about <span>631.7 N .
</span>That's it. It takes roughly a 142-pound pull on the string to keep
1 kilogram revolving at a 1-meter radius 4 times a second !<span>
</span>If you eased up on the string, the kilogram could keep revolving
in the same circle, but not as fast.
You also need to be very careful with this experiment, and use a string
that can hold up to a couple hundred pounds of tension without snapping.
If you've got that thing spinning at 4 times per second and the string breaks,
you've suddenly got a wild kilogram flying away from the circle in a straight
line, at 8π meters per second ... about 56 miles per hour ! This could definitely
be hazardous to the health of anybody who's been watching you and wondering
what you're doing.
Answer:
1.5X10^-4C
Explanation:
Expression for the electric force between the two charges is given by -
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = unknown
F=25N
q2 = 1.9x10^-6 C
r = 0.32 m
Substitute the given values in the above expression -
25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2
25= 17,100* (q1)/ 0.1024
multiply both sides by 0.1024 to get rid of the denominator
2.56=17,100*(q1)
Divide both sides by 17,100 to isolate q1
q1=1.5x10^-4C
