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DIA [1.3K]
3 years ago
9

70 POINTS AND BRAINLIEST PLEASE HELP!!!The Moon orbits Earth. This orbit causes the Moon to look different over the course of ab

out a month. These differences are called phases. One phase is called a full moon. Look closely at the table to the right. What can you conclude about a full moon? A. A. A full moon only occurs in the summer months. B. B. A full moon always occurs after a first quarter moon. C. C. A full moon always occurs on the 5th day of the month. D. D. A full moon always occurs before the first quarter moon.
Physics
1 answer:
Rudik [331]3 years ago
8 0

Answer:

It always acurs after a 1st quarter

do you have photo?

Explanation:

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Two long, parallel wires carry unequal currents in the same direction. The ratio of the currents is 3 to 1. The magnitude of the
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Answer:

3A is the larger of the two currents.

Explanation:

Let the currents in the two wires be I₁ and I₂

given:

Magnitude of the electric field, B = 4.0μT = 4.0×10⁻⁶T

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Now, the magnitude of a magnetic field at a distance 'R' due to the current 'I' is given as

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Where \mu_o is the magnitude constant = 4π×10⁻⁷ H/m

Thus, the magnitude of a magnetic field due to I₁ will be

B_1 = \frac{\mu_oI_1}{2\pi R}

B_2 = \frac{\mu_oI_2}{2\pi R}

given,

B = B₁ - B₂ (since both the currents are in the same direction and parallel)

substituting the values of B, B₁ and B₂

we get

4.0×10⁻⁶T =  \frac{\mu_oI_1}{2\pi R} - \frac{\mu_oI_2}{2\pi R}

or

4.0×10⁻⁶T =  \frac{\mu_o}{2\pi R}\times (I_1-I_2 )

also

\frac{I_1}{I_2} = \frac{3}{1}

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substituting the values in the above equation we get

4.0×10⁻⁶T =  \frac{4\pi\times 10^{-7}}{2\pi 0.1}\times (3 I_2-I_2)

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also

I_1 = 3\times I_2

⇒I_1 = 3\times 1A

⇒I_1 = 3A

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