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Murrr4er [49]
3 years ago
11

A school bus transporting students to school is an example of

Physics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

kinetic energy because it is taking the students to school.

Explanation:

As we know that bus is moving along with all students so here students are in motion with the bus

so as we know that kinetic energy is given as

KE = \frac{1}{2}mv^2

so here since all students and bus has some speed and since they are in motion so here the energy associated with them is kinetic energy

so here correct answer will be

kinetic energy because it is taking the students to school.

Andru [333]3 years ago
4 0
The last one, Kinetic energy bc it is taking them to school
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andreev551 [17]

Answer:

Polarization occurs when an electric field distorts the negative cloud of electrons around positive atomic nuclei in a direction opposite the field. Polarization P in its quantitative meaning is the amount of dipole moment p per unit volume V of a polarized material, P = p/V.

Explanation:

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2 years ago
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What description best describes both mirrors and lenses?
Kipish [7]
The only reasonable choice from this list is choice-A.
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The volume electric charge density of a solid sphere is given by the following equation: The variable r denotes the distance fro
qwelly [4]

Answer:

62.8 μC

Explanation:

Here is the complete question

The volume electric charge density of a solid sphere is given by the following equation: ρ = (0.2 mC/m⁵)r²The variable r denotes the distance from the center of the sphere, in spherical coordinates. What is the net electric charge (in μC) of the sphere if the radius of the sphere is 0.5 m?

Solution

The total charge on the sphere Q = ∫∫∫ρdV where ρ = volume charge density = 0.2r² and dV = volume element in spherical coordinates = r²sinθdθdrdΦ

So,  Q =  ∫∫∫ρdV

Q =  ∫∫∫ρr²sinθdθdrdΦ

Q =  ∫∫∫(0.2r²)r²sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

We integrate from r = 0 to r = 0.5 m, θ = 0 to π and Φ = 0 to 2π

So, Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴[∫sinθdθ]drdΦ

Q =  ∫∫0.2r⁴[-cosθ]drdΦ

Q =  ∫∫0.2r⁴-[cosπ - cos0]drdΦ

Q =  ∫∫∫0.2r⁴-[-1 - 1]drdΦ

Q =  ∫∫0.2r⁴-[- 2]drdΦ

Q =  ∫∫0.2r⁴(2)drdΦ

Q =  ∫∫0.4r⁴drdΦ

Q =  ∫0.4r⁴dr∫dΦ

Q =  ∫0.4r⁴dr[Φ]

Q =  ∫0.4r⁴dr[2π - 0]

Q =  ∫0.4r⁴dr[2π]

Q =  ∫0.8πr⁴dr

Q =  0.8π∫r⁴dr

Q =  0.8π[r⁵/5]

Q = 0.8π[(0.5 m)⁵/5 - (0 m)⁵/5]

Q = 0.8π[0.125 m⁵/5 - 0 m⁵/5]

Q = 0.8π[0.025 m⁵ - 0 m⁵]

Q = 0.8π[0.025 m⁵]

Q = (0.02π mC/m⁵) m⁵

Q = 0.0628 mC

Q = 0.0628 × 10⁻³ C

Q = 62.8 × 10⁻³ × 10⁻³ C

Q = 62.8 × 10⁻⁶ C

Q = 62.8 μC

3 0
2 years ago
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

P_{2}= 366.3004* 350

P2 = 128205.13 ≈ 128205 pascal.

<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>

5 0
2 years ago
A soccer ball is moving horizontally at a speed of 4.0 m/s. It then undergoes a constant acceleration. After 8.00 s, the ball is
CaHeK987 [17]

Answer: 0.0 m/s

Explanation

8 0
2 years ago
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