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3 years ago

A school bus transporting students to school is an example of

Physics

2 answers:

Makovka662 [10]3 years ago

8 0

Answer:

kinetic energy because it is taking the students to school.

Explanation:

As we know that bus is moving along with all students so here students are in motion with the bus

so as we know that kinetic energy is given as

$KE = \frac{1}{2}mv^2$

so here since all students and bus has some speed and since they are in motion so here the energy associated with them is kinetic energy

so here correct answer will be

kinetic energy because it is taking the students to school.

Andru [333]3 years ago

4 0

The last one, Kinetic energy bc it is taking them to school

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What scientific theory was the subject of the scopes trial?

ICE Princess25 [194]

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3 years ago

A uniform marble rolls down a symmetric bowl, starting from rest at the top of the left side. The top of each side is a distance

yan [13]

Answer:

a) h'= 5/7 h , b) h ’= h

Explanation:

Let's use energy conservation for this exercise

Starting point. Upper left side

Em₀ = mg h

Final point. Lower left side

Emf = K = ½ m v² + ½ I w²

Em₀ = emf

mgh = ½ m v² + ½ I w²

Angular and linear velocity are related

v = r w

w = v / r

The moment of inertia of the marble that we take as a solid sphere is

I = 2/5 m r²

We substitute

m g h = ½ m v² + ½ 2/5 m r² (v / r)²

g h = ½ v2 (1 + 2/5)

v = √(g h 10/7)

This is the speed at the bottom of the bowl

Now let's apply energy conservation to the right side

a) right side if rubbing

Em₀ = K

Emf = U = mg h’

½ m v² = mg h’

h’= ½ (g h 10/7) / g

h'= 5/7 h

b) right side with rubbing

Em₀ = K

Emf = K + U = -½ I w² + m g h

Emf = -½ 2/5 m r² v² / r² + m gh

Em₀ = emf

½ v² = -1/5 v² + g h’

h’= (1/2 +1/5) (gh 10/7) / g

h ’= h

c) When there is friction, an energy of rotation is accumulated that must be dissipated, by local it goes higher

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3 years ago

An object with charge -4.0μC is placed between a positively charged object to the

elena-s [515]

The net force on the -4.0μC object as a result of this net field will be -10.4 N.

<h3>What is the charge?</h3>

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

$\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N$

Electric field intensity on the negative charge:

$\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N$

The net charge is the algebraic sum of the two charges;

$\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N$

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

To learn more about the charge refer to the link;

brainly.com/question/24391667

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2 years ago

The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm

Colt1911 [192]

The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
$E=- \frac{13.6}{n^2} [eV]$
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
$\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2} )[eV]=3.02 eV$
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this $\Delta E$ . Converting it into Joule,
$\Delta E=3.02 eV=4.84 \cdot 10^{-19}J$
The energy of the photon is
$E=hf$
where h is the Planck constant while f is its frequency. Writing $\Delta E=hf$ , we can write the frequency f of the photon:
$f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz$

The photon travels at the speed of light, $c=3 \cdot 10^8 m/s$ , so its wavelength is
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm$

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.

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4 years ago

Read 2 more answers

Explain the relationship between brightness and distance. Explain by relating the brightness of the light to the energy of the l

Iteru [2.4K]

Answer:

What part of the light wave is related to the brightness of the light?

Amplitude

The amplitude of a wave tells us about the intensity or brightness of the light relative to other light waves of the same wavelength

The brightness of light is related to intensity or the amount of light an object emits or reflects. Brightness depends on light wave amplitude, the height of light waves. Brightness is also somewhat influenced by wavelength.

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3 years ago